Concept-wise Practice

simplify-radicals MCQ Questions for Class 10

simplify-radicals se related questions ko ek jagah revise karein. Har question me bilingual content, answer feedback aur explanation available hai.

Practice Questions

3 questions tagged with simplify-radicals.

Question 1/3 Easy Mathematics Chapter 1: Real Numbers 5: Irrational numbers Class 10 Level 14

\(\sqrt{48}\) को सरल करने पर क्या मिलेगा?

What do we get after simplifying \(\sqrt{48}\)?

Explanation opens after your attempt
Correct Answer

A. \(4\sqrt{3}\)

Step 1

Concept

\(48=16 \times 3\).

Step 2

Why this answer is correct

\(\sqrt{48}=\sqrt{16 \times 3}=4\sqrt{3}\).

Step 3

Exam Tip

Using the largest perfect square gives the simplest form. चरण 1: \(48=16 \times 3\) है। चरण 2: \(\sqrt{48}=\sqrt{16 \times 3}=4\sqrt{3}\)। चरण 3: सबसे बड़ा पूर्ण वर्ग लेने से सरल रूप सही और छोटा मिलता है।

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Question 2/3 Easy Mathematics Chapter 1: Real Numbers 5: Irrational numbers Class 10 Level 13

\(\sqrt{75}\) का सरल रूप क्या है?

What is the simplified form of \(\sqrt{75}\)?

Explanation opens after your attempt
Correct Answer

A. \(5\sqrt{3}\)

Step 1

Concept

Write \(75=25 \times 3\).

Step 2

Why this answer is correct

\(\sqrt{75}=\sqrt{25 \times 3}=5\sqrt{3}\).

Step 3

Exam Tip

While simplifying a square root, split the inside number into a perfect square and the remaining factor. चरण 1: \(75=25 \times 3\) लिखें। चरण 2: \(\sqrt{75}=\sqrt{25 \times 3}=5\sqrt{3}\)। चरण 3: वर्गमूल को सरल करते समय अंदर की संख्या को पूर्ण वर्ग और बाकी गुणनखंड में तोड़ें।

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Question 3/3 Easy Mathematics Chapter 1: Real Numbers 5: Irrational numbers Class 10 Level 13

\(\sqrt{27}\) का सरल रूप क्या है?

What is the simplified form of \(\sqrt{27}\)?

Explanation opens after your attempt
Correct Answer

A. \(3\sqrt{3}\)

Step 1

Concept

Write \(27=9 \times 3\).

Step 2

Why this answer is correct

\(\sqrt{27}=\sqrt{9 \times 3}=3\sqrt{3}\).

Step 3

Exam Tip

When (9) appears as a factor inside a square root, take it out as (3). चरण 1: \(27=9 \times 3\) लिखें। चरण 2: \(\sqrt{27}=\sqrt{9 \times 3}=3\sqrt{3}\)। चरण 3: वर्गमूल में पूर्ण वर्ग (9) दिखे तो उसे बाहर (3) के रूप में निकालें।

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