Concept-wise Practice

quadratic-zeroes MCQ Questions for Class 10

quadratic-zeroes se related questions ko ek jagah revise karein. Har question me bilingual content, answer feedback aur explanation available hai.

Practice Questions

4 questions tagged with quadratic-zeroes.

यदि (p(x)=x-2-8x+13), तो इसके शून्यक कौन से हैं?

If (p(x)=x-2-8x+13), what are its zeroes?

Explanation opens after your attempt
Correct Answer

A. \(4+\sqrt{3}\) और \(4-\sqrt{3}\)\(4+\sqrt{3}\) and \(4-\sqrt{3}\)

Step 1

Concept

Using the quadratic formula \(x=\frac{8\pm\sqrt{64-52}}{2}=4\pm\sqrt{3}\). In exams simplify the discriminant.

Step 2

Why this answer is correct

The correct answer is A. \(4+\sqrt{3}\) और \(4-\sqrt{3}\) / \(4+\sqrt{3}\) and \(4-\sqrt{3}\). Using the quadratic formula \(x=\frac{8\pm\sqrt{64-52}}{2}=4\pm\sqrt{3}\). In exams simplify the discriminant.

Step 3

Exam Tip

द्विघात सूत्र से \(x=\frac{8\pm\sqrt{64-52}}{2}=4\pm\sqrt{3}\) मिलता है। परीक्षा में विविक्तकर को सरल करें।

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यदि (p(x)=x-2-4x-1), तो इसके शून्यक कौन से हैं?

If (p(x)=x-2-4x-1), what are its zeroes?

Explanation opens after your attempt
Correct Answer

A. \(2+\sqrt{5}\) और \(2-\sqrt{5}\)\(2+\sqrt{5}\) and \(2-\sqrt{5}\)

Step 1

Concept

Using the quadratic formula, \(x=\frac{4\pm\sqrt{16+4}}{2}=2\pm\sqrt{5}\). In exams simplify the discriminant.

Step 2

Why this answer is correct

The correct answer is A. \(2+\sqrt{5}\) और \(2-\sqrt{5}\) / \(2+\sqrt{5}\) and \(2-\sqrt{5}\). Using the quadratic formula, \(x=\frac{4\pm\sqrt{16+4}}{2}=2\pm\sqrt{5}\). In exams simplify the discriminant.

Step 3

Exam Tip

द्विघात सूत्र से \(x=\frac{4\pm\sqrt{16+4}}{2}=2\pm\sqrt{5}\) मिलता है। परीक्षा में विविक्तकर को सरल करें।

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यदि (p(x)=-x-2+25), तो ग्राफ के वास्तविक शून्यक कौन से होंगे?

If (p(x)=-x-2+25), what will be the real zeroes of the graph?

Explanation opens after your attempt
Correct Answer

A. (5) और (-5)(5) and (-5)

Step 1

Concept

From \(-x^2+25=0\), \(x^2=25\), so \(x=\pm5\). Tip: even with a negative sign, set (y=0).

Step 2

Why this answer is correct

The correct answer is A. (5) और (-5) / (5) and (-5). From \(-x^2+25=0\), \(x^2=25\), so \(x=\pm5\). Tip: even with a negative sign, set (y=0).

Step 3

Exam Tip

\(-x^2+25=0\) से \(x^2=25\), इसलिए \(x=\pm5\) है। टिप: ऋण चिह्न देखकर भी (y=0) रखना न भूलें।

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किस स्थिति में द्विघात बहुपद के दो वास्तविक शून्यक होंगे?

In which case will a quadratic polynomial have two real zeroes?

Explanation opens after your attempt
Correct Answer

A. जब उसका ग्राफ (x)-अक्ष को दो अलग बिंदुओं पर काटेWhen its graph cuts the (x)-axis at two distinct points

Step 1

Concept

Real zeroes of a quadratic polynomial are found from points where it meets the (x)-axis. Two distinct intersections give two real zeroes.

Step 2

Why this answer is correct

The correct answer is A. जब उसका ग्राफ (x)-अक्ष को दो अलग बिंदुओं पर काटे / When its graph cuts the (x)-axis at two distinct points. Real zeroes of a quadratic polynomial are found from points where it meets the (x)-axis. Two distinct intersections give two real zeroes.

Step 3

Exam Tip

द्विघात बहुपद के वास्तविक शून्यक (x)-अक्ष से मिलने वाले बिंदुओं से मिलते हैं। दो अलग कटाव दो वास्तविक शून्यक देते हैं।

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