Concept-wise Practice

powers-of-5 MCQ Questions for Class 10

powers-of-5 se related questions ko ek jagah revise karein. Har question me bilingual content, answer feedback aur explanation available hai.

Practice Questions

5 questions tagged with powers-of-5.

\(\frac{81}{2^4\cdot 3^4\cdot 5^6}\) का दशमलव प्रसार कितने स्थानों पर समाप्त होगा?

After how many decimal places will \(\frac{81}{2^4\cdot 3^4\cdot 5^6}\) terminate?

Explanation opens after your attempt
Correct Answer

C. (6)

Step 1

Concept

Since \(81=3^4\), the reduced denominator is \(2^4\cdot 5^6\). The larger exponent is (6), so the decimal terminates after (6) places.

Step 2

Why this answer is correct

The correct answer is C. (6). Since \(81=3^4\), the reduced denominator is \(2^4\cdot 5^6\). The larger exponent is (6), so the decimal terminates after (6) places.

Step 3

Exam Tip

\(81=3^4\) कटने पर हर \(2^4\cdot 5^6\) बचेगा। बड़ी घात (6) है इसलिए दशमलव (6) स्थानों पर समाप्त होगा।

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\(\frac{72}{2^3\cdot 3^2\cdot 5^5}\) का दशमलव प्रसार कितने स्थानों पर समाप्त होगा?

After how many decimal places will \(\frac{72}{2^3\cdot 3^2\cdot 5^5}\) terminate?

Explanation opens after your attempt
Correct Answer

C. (5)

Step 1

Concept

Since \(72=2^3\cdot 3^2\), the reduced denominator is \(5^5\). The decimal terminates after (5) places.

Step 2

Why this answer is correct

The correct answer is C. (5). Since \(72=2^3\cdot 3^2\), the reduced denominator is \(5^5\). The decimal terminates after (5) places.

Step 3

Exam Tip

\(72=2^3\cdot 3^2\), इसलिए कटौती के बाद हर \(5^5\) बचता है। दशमलव (5) स्थानों पर समाप्त होगा।

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\(\frac{9}{15625}\) का दशमलव प्रसार कितने स्थानों पर समाप्त होगा?

After how many decimal places will the decimal expansion of \(\frac{9}{15625}\) terminate?

Explanation opens after your attempt
Correct Answer

C. (6)

Step 1

Concept

\(15625=5^6\).

Step 2

Why this answer is correct

The powers are (0) for (2) and (6) for (5). So the larger exponent is (6).

Step 3

Exam Tip

Practise identifying higher powers of (5). चरण 1: \(15625=5^6\) है। चरण 2: हर में (2) की घात (0) और (5) की घात (6) है। इसलिए बड़ी घात (6) होगी। चरण 3: (5) की बड़ी घातों को पहचानने का अभ्यास करें।

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किस भिन्न का दशमलव प्रसार ठीक (6) स्थानों पर समाप्त होगा?

Which fraction has a decimal expansion terminating exactly after (6) places?

Explanation opens after your attempt
Correct Answer

B. \(\frac{9}{64000}\)

Step 1

Concept

\(64000=2^9\cdot 5^3\), so it would give (9) places, not (6).

Step 2

Why this answer is correct

\(15625=5^6\), so \(\frac{9}{15625}\) terminates exactly after (6) places.

Step 3

Exam Tip

Calculate prime powers carefully. चरण 1: \(64000=2^9\cdot 5^3\) नहीं, बल्कि \(64000=64\cdot 1000=2^6\cdot 2^3\cdot 5^3=2^9\cdot 5^3\) है। यह (9) स्थान देगा, इसलिए विकल्प (B) सही नहीं हो सकता। चरण 2: \(15625=5^6\), इसलिए \(\frac{9}{15625}\) ठीक (6) स्थानों पर समाप्त होगा। चरण 3: घातों की गणना सावधानी से करें।

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\(\frac{13}{3125}\) के दशमलव प्रसार में कितने दशमलव स्थान होंगे?

How many decimal places will the decimal expansion of \(\frac{13}{3125}\) have?

Explanation opens after your attempt
Correct Answer

C. (5)

Step 1

Concept

\(3125=5^5\).

Step 2

Why this answer is correct

The denominator has power (0) of (2) and power (5) of (5). So the decimal terminates after (5) places.

Step 3

Exam Tip

Remembering \(3125=5^5\) helps in quick factorisation. चरण 1: \(3125=5^5\) है। चरण 2: हर में (2) की घात (0) और (5) की घात (5) है। इसलिए दशमलव (5) स्थानों पर समाप्त होगा। चरण 3: (5) की घातें पहचानने के लिए \(3125=5^5\) याद रखना उपयोगी है।

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