समीकरण \(x^2+6x+13=0\) की मूल प्रकृति क्या होगी?
What will be the nature of roots of \(x^2+6x+13=0\)?
Explanation opens after your attempt
Correct Answer
A. कोई वास्तविक मूल नहीं ((D=-16))No real roots ((D=-16))
Concept
Here (D=62-4(1)(13)=-16). When (D<0), the graph does not cut the (x)-axis.
Why this answer is correct
The correct answer is A. कोई वास्तविक मूल नहीं ((D=-16)) / No real roots ((D=-16)). Here (D=62-4(1)(13)=-16). When (D<0), the graph does not cut the (x)-axis.
Exam Tip
यहाँ (D=62-4(1)(13)=-16) है। (D<0) होने पर ग्राफ (x)-अक्ष को नहीं काटता।
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