Concept-wise Practice

denominator-conversion MCQ Questions for Class 10

denominator-conversion se related questions ko ek jagah revise karein. Har question me bilingual content, answer feedback aur explanation available hai.

Practice Questions

5 questions tagged with denominator-conversion.

\(\frac{11}{2^8\cdot 5^5}\) को \(\frac{N}{10^8}\) में बदलने पर (N) क्या होगा?

When \(\frac{11}{2^8\cdot 5^5}\) is converted into \(\frac{N}{10^8}\), what is (N)?

Explanation opens after your attempt
Correct Answer

B. (1375)

Step 1

Concept

Since \(10^8=2^8\cdot 5^8\), the denominator lacks \(5^3\). Thus \(N=11\cdot 125=1375\).

Step 2

Why this answer is correct

The correct answer is B. (1375). Since \(10^8=2^8\cdot 5^8\), the denominator lacks \(5^3\). Thus \(N=11\cdot 125=1375\).

Step 3

Exam Tip

\(10^8=2^8\cdot 5^8\) है इसलिए हर में \(5^3\) की कमी है। \(N=11\cdot 125=1375\) होगा।

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\(\frac{7}{2^6\cdot 5^4}\) को \(\frac{N}{10^6}\) में बदलने पर (N) क्या होगा?

When \(\frac{7}{2^6\cdot 5^4}\) is converted into \(\frac{N}{10^6}\), what is (N)?

Explanation opens after your attempt
Correct Answer

B. (175)

Step 1

Concept

Since \(10^6=2^6\cdot 5^6\), the denominator lacks \(5^2\). Thus \(N=7\cdot 25=175\).

Step 2

Why this answer is correct

The correct answer is B. (175). Since \(10^6=2^6\cdot 5^6\), the denominator lacks \(5^2\). Thus \(N=7\cdot 25=175\).

Step 3

Exam Tip

\(10^6=2^6\cdot 5^6\) है इसलिए हर में \(5^2\) की कमी है। \(N=7\cdot 25=175\) होगा।

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\(\frac{3}{2^4\cdot 5^6}\) को \(\frac{N}{10^6}\) में बदलने पर (N) क्या होगा?

When \(\frac{3}{2^4\cdot 5^6}\) is converted into \(\frac{N}{10^6}\), what is (N)?

Explanation opens after your attempt
Correct Answer

B. (12)

Step 1

Concept

Since \(10^6=2^6\cdot 5^6\), the denominator lacks \(2^2\). Thus \(N=3\cdot 4=12\).

Step 2

Why this answer is correct

The correct answer is B. (12). Since \(10^6=2^6\cdot 5^6\), the denominator lacks \(2^2\). Thus \(N=3\cdot 4=12\).

Step 3

Exam Tip

\(10^6=2^6\cdot 5^6\), इसलिए हर में \(2^2\) की कमी है। \(N=3\cdot 4=12\) होगा।

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\(\frac{1}{2^5\cdot 5^8}\) के हर को \(10^8\) बनाने के लिए किससे गुणा करना होगा?

By what should the denominator of \(\frac{1}{2^5\cdot 5^8}\) be multiplied to make it \(10^8\)?

Explanation opens after your attempt
Correct Answer

A. \(2^3\)

Step 1

Concept

\(10^8=2^8\cdot 5^8\).

Step 2

Why this answer is correct

The given denominator is \(2^5\cdot 5^8\), so it lacks \(2^3\).

Step 3

Exam Tip

To form \(10^k\), increase the prime factor with the smaller exponent. चरण 1: \(10^8=2^8\cdot 5^8\) होता है। चरण 2: दिए गए हर में \(2^5\cdot 5^8\) है, इसलिए \(2^3\) की कमी है। चरण 3: \(10^k\) बनाने के लिए कम घात वाले अभाज्य गुणनखंड को बढ़ाएँ।

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\(\frac{1}{2^4\cdot 5^6}\) के हर को \(10^6\) बनाने के लिए अंश और हर को किससे गुणा करना चाहिए?

By what should numerator and denominator of \(\frac{1}{2^4\cdot 5^6}\) be multiplied to make the denominator \(10^6\)?

Explanation opens after your attempt
Correct Answer

A. \(2^2\)

Step 1

Concept

\(10^6=2^6\cdot 5^6\).

Step 2

Why this answer is correct

The denominator \(2^4\cdot 5^6\) lacks \(2^2\). So multiply numerator and denominator by \(2^2\).

Step 3

Exam Tip

Complete the deficiency of the prime with the smaller exponent. चरण 1: \(10^6=2^6\cdot 5^6\) होता है। चरण 2: हर \(2^4\cdot 5^6\) में \(2^2\) की कमी है। इसलिए अंश और हर को \(2^2\) से गुणा करेंगे। चरण 3: जिसकी घात कम हो, उसी की कमी पूरी करें।

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