\(x^2-11x+b\) में यदि गुणनखंड ((x-6)(x-5)) हैं तो (b) क्या है?
If the factors of \(x^2-11x+b\) are ((x-6)(x-5)), what is (b)?
Explanation opens after your attempt
Correct Answer
B. (30)
Concept
((x-6)(x-5)=x-2-11x+30). Therefore the constant term is (b=30).
Why this answer is correct
The correct answer is B. (30). ((x-6)(x-5)=x-2-11x+30). Therefore the constant term is (b=30).
Exam Tip
((x-6)(x-5)=x-2-11x+30) है। इसलिए स्थिर पद (b=30) है।
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