\(x^2-11x+b\) में यदि गुणनखंड ((x-6)(x-5)) हैं तो (b) क्या है?

If the factors of \(x^2-11x+b\) are ((x-6)(x-5)), what is (b)?

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Correct Answer

B. (30)

Step 1

Concept

((x-6)(x-5)=x-2-11x+30). Therefore the constant term is (b=30).

Step 2

Why this answer is correct

The correct answer is B. (30). ((x-6)(x-5)=x-2-11x+30). Therefore the constant term is (b=30).

Step 3

Exam Tip

((x-6)(x-5)=x-2-11x+30) है। इसलिए स्थिर पद (b=30) है।

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Mathematics Answer, Explanation and Revision Hints

\(x^2-11x+b\) में यदि गुणनखंड ((x-6)(x-5)) हैं तो (b) क्या है? / If the factors of \(x^2-11x+b\) are ((x-6)(x-5)), what is (b)?

Correct Answer: B. (30). Explanation: ((x-6)(x-5)=x-2-11x+30) है। इसलिए स्थिर पद (b=30) है। / ((x-6)(x-5)=x-2-11x+30). Therefore the constant term is (b=30).

Which concept should I revise for this Mathematics MCQ?

((x-6)(x-5)=x-2-11x+30). Therefore the constant term is (b=30).

What exam hint can help solve this Mathematics question?

((x-6)(x-5)=x-2-11x+30) है। इसलिए स्थिर पद (b=30) है।