Concept-wise Practice

always real distinct MCQ Questions for Class 10

always real distinct se related questions ko ek jagah revise karein. Har question me bilingual content, answer feedback aur explanation available hai.

Practice Questions

2 questions tagged with always real distinct.

यदि (x-2-2(k-3)x+k-2-6k+8=0) है, तो मूलों की प्रकृति क्या है?

If (x-2-2(k-3)x+k-2-6k+8=0), what is the nature of roots?

Explanation opens after your attempt
Correct Answer

A. हमेशा वास्तविक और भिन्नAlways real and distinct

Step 1

Concept

Here (D=4(k-3)2-4\(k^2-6k+8\)=4>0). Therefore roots are always real and distinct.

Step 2

Why this answer is correct

The correct answer is A. हमेशा वास्तविक और भिन्न / Always real and distinct. Here (D=4(k-3)2-4\(k^2-6k+8\)=4>0). Therefore roots are always real and distinct.

Step 3

Exam Tip

यहाँ (D=4(k-3)2-4\(k^2-6k+8\)=4>0) है। इसलिए मूल हमेशा वास्तविक और भिन्न हैं।

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समीकरण (2x-2-4ax+\(2a^2-3\)=0) के मूलों की प्रकृति क्या है?

What is the nature of roots of (2x-2-4ax+\(2a^2-3\)=0)?

Explanation opens after your attempt
Correct Answer

A. हमेशा वास्तविक और भिन्नAlways real and distinct

Step 1

Concept

Here (D=(-4a)2-4(2)\(2a^2-3\)=24>0). Thus roots are always real and distinct.

Step 2

Why this answer is correct

The correct answer is A. हमेशा वास्तविक और भिन्न / Always real and distinct. Here (D=(-4a)2-4(2)\(2a^2-3\)=24>0). Thus roots are always real and distinct.

Step 3

Exam Tip

यहाँ (D=(-4a)2-4(2)\(2a^2-3\)=24>0) है। इसलिए मूल हमेशा वास्तविक और भिन्न हैं।

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AI Video Prompt 16:9 + 9:16

Is question ka premium MCQ video banane ke liye ready prompt. Copy karke Sora, Runway, Canva AI, CapCut AI, ChatGPT video workflow ya editor me use karein.

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