यदि (x-2-2(k-3)x+k-2-6k+8=0) है, तो मूलों की प्रकृति क्या है?
If (x-2-2(k-3)x+k-2-6k+8=0), what is the nature of roots?
Explanation opens after your attempt
A. हमेशा वास्तविक और भिन्नAlways real and distinct
Concept
Here (D=4(k-3)2-4\(k^2-6k+8\)=4>0). Therefore roots are always real and distinct.
Why this answer is correct
The correct answer is A. हमेशा वास्तविक और भिन्न / Always real and distinct. Here (D=4(k-3)2-4\(k^2-6k+8\)=4>0). Therefore roots are always real and distinct.
Exam Tip
यहाँ (D=4(k-3)2-4\(k^2-6k+8\)=4>0) है। इसलिए मूल हमेशा वास्तविक और भिन्न हैं।
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