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11 results found for "input" in Class 10.

Question Easy Mathematics Polynomials Geometrical meaning of the zeroes of a polynomial. Class 10 Level 23

ग्राफ में बिंदु ((-8,0)) दिखने पर बहुपद का कौन-सा मान शून्य होगा?

If the point ((-8,0)) appears on the graph, which value of the polynomial input gives zero?

Explanation opens after your attempt
Correct Answer

A. (x=-8)

Step 1

Concept

The point ((-8,0)) means (y=0) at (x=-8). So (x=-8) makes the polynomial zero.

Step 2

Why this answer is correct

The correct answer is A. (x=-8). The point ((-8,0)) means (y=0) at (x=-8). So (x=-8) makes the polynomial zero.

Step 3

Exam Tip

((-8,0)) का अर्थ है (x=-8) पर (y=0)। इसलिए (x=-8) बहुपद को शून्य बनाता है।

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Question Expert Mathematics Polynomials Polynomials in one variable Class 10 Level 47

यदि (p(x)=3x-3-12x), तो (p(-2)+p(2)) का मान क्या है?

If (p(x)=3x-3-12x), what is the value of (p(-2)+p(2))?

Explanation opens after your attempt
Correct Answer

B. (0)

Step 1

Concept

(p(-2)=0) and (p(2)=0), so the sum is (0). Handle signs carefully for opposite inputs.

Step 2

Why this answer is correct

The correct answer is B. (0). (p(-2)=0) and (p(2)=0), so the sum is (0). Handle signs carefully for opposite inputs.

Step 3

Exam Tip

(p(-2)=0) और (p(2)=0), इसलिए योग (0) है। विपरीत मानों पर संकेतों को सावधानी से रखें।

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Question Expert Mathematics Polynomials Polynomials in one variable Class 10 Level 46

यदि (p(x)=ax-2+bx+c) में \(a\neq0\) है और (p(1)=p(-1)=0) है, तो (b) का मान क्या होगा?

If (p(x)=ax-2+bx+c) with \(a\neq0\) and (p(1)=p(-1)=0), what is the value of (b)?

Explanation opens after your attempt
Correct Answer

A. (0)

Step 1

Concept

(p(1)=a+b+c) and (p(-1)=a-b+c); subtracting gives (2b=0). In exams, use addition or subtraction for symmetric inputs.

Step 2

Why this answer is correct

The correct answer is A. (0). (p(1)=a+b+c) and (p(-1)=a-b+c); subtracting gives (2b=0). In exams, use addition or subtraction for symmetric inputs.

Step 3

Exam Tip

(p(1)=a+b+c) और (p(-1)=a-b+c) हैं, घटाने पर (2b=0) मिलता है। परीक्षा में सममित मानों पर जोड़-घटाव जल्दी करें।

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Question Hard Mathematics Polynomials Polynomials in one variable Class 10 Level 48

यदि (p(x)=2x-3-8x), तो (p(-2)+p(2)) का मान क्या है?

If (p(x)=2x-3-8x), what is the value of (p(-2)+p(2))?

Explanation opens after your attempt
Correct Answer

B. (0)

Step 1

Concept

(p(-2)=0) and (p(2)=0), so the sum is (0). Handle signs carefully for opposite inputs.

Step 2

Why this answer is correct

The correct answer is B. (0). (p(-2)=0) and (p(2)=0), so the sum is (0). Handle signs carefully for opposite inputs.

Step 3

Exam Tip

(p(-2)=0) और (p(2)=0), इसलिए योग (0) है। विपरीत मानों पर संकेतों को सावधानी से रखें।

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Question Hard Mathematics Polynomials Polynomials in one variable Class 10 Level 47

यदि (p(x)=x-3-4x), तो (p(-2)+p(2)) का मान क्या है?

If (p(x)=x-3-4x), what is the value of (p(-2)+p(2))?

Explanation opens after your attempt
Correct Answer

B. (0)

Step 1

Concept

(p(-2)=0) and (p(2)=0), so the sum is (0). It behaves like an odd polynomial.

Step 2

Why this answer is correct

The correct answer is B. (0). (p(-2)=0) and (p(2)=0), so the sum is (0). It behaves like an odd polynomial.

Step 3

Exam Tip

(p(-2)=0) और (p(2)=0), इसलिए योग (0) है। यह विषम बहुपद जैसा व्यवहार करता है।

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Question Medium Mathematics Polynomials Polynomials in one variable Class 10 Level 48

(q(x)=x-3+2x-2-5x-6) के लिए (q(-2)) क्या होगा?

For (q(x)=x-3+2x-2-5x-6), what is (q(-2))?

Explanation opens after your attempt
Correct Answer

C. (4)

Step 1

Concept

(q(-2)=-8+8+10-6=4). Check the sign of every term separately when substituting a negative value.

Step 2

Why this answer is correct

The correct answer is C. (4). (q(-2)=-8+8+10-6=4). Check the sign of every term separately when substituting a negative value.

Step 3

Exam Tip

(q(-2)=-8+8+10-6=4)। ऋणात्मक मान रखते समय प्रत्येक पद का संकेत अलग जांचें।

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Question Easy Mathematics Polynomials Polynomials in one variable Class 10 Level 48

यदि (p(x)=x-2+x) है, तो (p(-1)) क्या होगा?

If (p(x)=x-2+x), what is (p(-1))?

Explanation opens after your attempt
Correct Answer

A. (0)

Step 1

Concept

(p(-1)=(-1)2+(-1)=1-1=0). The square of a negative number is positive.

Step 2

Why this answer is correct

The correct answer is A. (0). (p(-1)=(-1)2+(-1)=1-1=0). The square of a negative number is positive.

Step 3

Exam Tip

(p(-1)=(-1)2+(-1)=1-1=0) है। ऋणात्मक संख्या का वर्ग धनात्मक होता है।

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Question Easy Mathematics Polynomials Polynomials in one variable Class 10 Level 48

(p(x)=x-2+2x+1) में (p(0)) का मान क्या है?

For (p(x)=x-2+2x+1), what is (p(0))?

Explanation opens after your attempt
Correct Answer

B. (1)

Step 1

Concept

(p(0)=02+2\cdot0+1=1). When (x=0), only the constant term remains.

Step 2

Why this answer is correct

The correct answer is B. (1). (p(0)=02+2\cdot0+1=1). When (x=0), only the constant term remains.

Step 3

Exam Tip

(p(0)=02+2\cdot0+1=1) है। (x=0) रखने पर केवल नियत पद बचता है।

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Question Expert Mathematics Polynomials Irrational numbers and real numbers Class 10 Level 25

यदि (p(x)=x-2-2x-2) है, तो (p\(1+\sqrt{3}\)) क्या है?

If (p(x)=x-2-2x-2), what is (p\(1+\sqrt{3}\))?

Explanation opens after your attempt
Correct Answer

A. (0)

Step 1

Concept

(\(1+\sqrt{3}\)2-2\(1+\sqrt{3}\)-2=1+2\sqrt{3}+3-2-2\sqrt{3}-2=0). Do not forget the middle term while expanding the square.

Step 2

Why this answer is correct

The correct answer is A. (0). (\(1+\sqrt{3}\)2-2\(1+\sqrt{3}\)-2=1+2\sqrt{3}+3-2-2\sqrt{3}-2=0). Do not forget the middle term while expanding the square.

Step 3

Exam Tip

(\(1+\sqrt{3}\)2-2\(1+\sqrt{3}\)-2=1+2\sqrt{3}+3-2-2\sqrt{3}-2=0)। वर्ग खोलते समय बीच का पद न भूलें।

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Question Expert Mathematics Polynomials Irrational numbers and real numbers Class 10 Level 25

यदि (p\(\sqrt{5}\)=0) और (p(x)=x-2+ax-5) है, तो (a) का मान क्या है?

If (p\(\sqrt{5}\)=0) and (p(x)=x-2+ax-5), what is the value of (a)?

Explanation opens after your attempt
Correct Answer

A. (0)

Step 1

Concept

Substitution gives \(5+a\sqrt{5}-5=0\), so \(a\sqrt{5}=0\) and (a=0). Simplify like terms first while substituting.

Step 2

Why this answer is correct

The correct answer is A. (0). Substitution gives \(5+a\sqrt{5}-5=0\), so \(a\sqrt{5}=0\) and (a=0). Simplify like terms first while substituting.

Step 3

Exam Tip

रखने पर \(5+a\sqrt{5}-5=0\), इसलिए \(a\sqrt{5}=0\) और (a=0)। मान रखते समय समान पद पहले सरल करें।

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Question Hard Mathematics Polynomials Irrational numbers and real numbers Class 10 Level 27

यदि (p(x)=x-2-2x-2) है, तो (p\(\sqrt{2}\)) का मान क्या है?

If (p(x)=x-2-2x-2), what is the value of (p\(\sqrt{2}\))?

Explanation opens after your attempt
Correct Answer

A. \(-2\sqrt{2}\)

Step 1

Concept

(p\(\sqrt{2}\)=\(\sqrt{2}\)2-2\sqrt{2}-2=2-2\sqrt{2}-2=-2\sqrt{2}). When substituting, write (\(\sqrt{2}\)2=2).

Step 2

Why this answer is correct

The correct answer is A. \(-2\sqrt{2}\). (p\(\sqrt{2}\)=\(\sqrt{2}\)2-2\sqrt{2}-2=2-2\sqrt{2}-2=-2\sqrt{2}). When substituting, write (\(\sqrt{2}\)2=2).

Step 3

Exam Tip

(p\(\sqrt{2}\)=\(\sqrt{2}\)2-2\sqrt{2}-2=2-2\sqrt{2}-2=-2\sqrt{2}) है। मान रखते समय (\(\sqrt{2}\)2=2) लिखें।

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