17 results found for "degrees kilometres" in Class 10.
एक नाव शांत जल में (20) किलोमीटर प्रति घंटा चलती है। धारा की गति (x) है। (48) किलोमीटर धारा के साथ और (32) किलोमीटर धारा के विरुद्ध जाने में कुल (4) घंटे लगते हैं। (x) क्या है?
A boat moves at (20) kilometres per hour in still water. The stream speed is (x). It takes (4) hours to go (48) kilometres downstream and (32) kilometres upstream. What is (x)?
#quadratic-equations
#word-problems
#boat-stream
A (4)
B (3)
C (5)
D (2)
Explanation opens after your attempt
Step 1
Concept
The equation is \(\frac{48}{20+x}+\frac{32}{20-x}=4\). Substituting (x=4) gives time (2+2=4) hours.
Step 2
Why this answer is correct
The correct answer is A. (4). The equation is \(\frac{48}{20+x}+\frac{32}{20-x}=4\). Substituting (x=4) gives time (2+2=4) hours.
Step 3
Exam Tip
समीकरण \(\frac{48}{20+x}+\frac{32}{20-x}=4\) है। (x=4) रखने पर समय (2+2=4) घंटे मिलता है।
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एक व्यक्ति (300) किलोमीटर यात्रा करता है। गति (10) किलोमीटर प्रति घंटा कम करने पर समय (1) घंटा बढ़ जाता है। मूल गति क्या है?
A person travels (300) kilometres. If the speed is reduced by (10) kilometres per hour, the time increases by (1) hour. What is the original speed?
#quadratic-equations
#word-problems
#speed-change
A (60)
B (50)
C (40)
D (30)
Explanation opens after your attempt
Step 1
Concept
Let the original speed be (x), then \(\frac{300}{x-10}-\frac{300}{x}=1\). Solving gives (x=60).
Step 2
Why this answer is correct
The correct answer is A. (60). Let the original speed be (x), then \(\frac{300}{x-10}-\frac{300}{x}=1\). Solving gives (x=60).
Step 3
Exam Tip
मूल गति (x) हो, तो \(\frac{300}{x-10}-\frac{300}{x}=1\)। हल करने पर (x=60) मिलता है।
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एक ट्रेन (360) किलोमीटर दूरी तय करती है। गति (15) किलोमीटर प्रति घंटा बढ़ाने पर समय (2) घंटे कम हो जाता है। मूल गति क्या है?
A train covers (360) kilometres. If its speed is increased by (15) kilometres per hour, the time decreases by (2) hours. What is the original speed?
#quadratic-equations
#word-problems
#speed-time
A (45)
B (60)
C (30)
D (40)
Explanation opens after your attempt
Step 1
Concept
Let the original speed be (x), then \(\frac{360}{x}-\frac{360}{x+15}=2\). Solving gives (x=45).
Step 2
Why this answer is correct
The correct answer is A. (45). Let the original speed be (x), then \(\frac{360}{x}-\frac{360}{x+15}=2\). Solving gives (x=45).
Step 3
Exam Tip
मूल गति (x) हो, तो \(\frac{360}{x}-\frac{360}{x+15}=2\)। हल करने पर (x=45) मिलता है।
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एक बस (180) किलोमीटर दूरी तय करती है। गति (15) किलोमीटर प्रति घंटा बढ़ाने पर समय (1) घंटा कम हो जाता है। मूल गति क्या है?
A bus covers (180) kilometres. If its speed is increased by (15) kilometres per hour, the time decreases by (1) hour. What is the original speed?
#quadratic-equations
#word-problems
#speed-time
A (45)
B (60)
C (30)
D (40)
Explanation opens after your attempt
Step 1
Concept
Let the original speed be (x), then \(\frac{180}{x}-\frac{180}{x+15}=1\). Solving gives (x=45).
Step 2
Why this answer is correct
The correct answer is A. (45). Let the original speed be (x), then \(\frac{180}{x}-\frac{180}{x+15}=1\). Solving gives (x=45).
Step 3
Exam Tip
मूल गति (x) हो, तो \(\frac{180}{x}-\frac{180}{x+15}=1\)। हल करने पर (x=45) मिलता है।
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एक नाव शांत जल में (15) किलोमीटर प्रति घंटा चलती है। धारा की गति (x) है। (36) किलोमीटर धारा के साथ और (24) किलोमीटर धारा के विरुद्ध जाने में कुल (4) घंटे लगते हैं। (x) क्या है?
A boat moves at (15) kilometres per hour in still water. The stream speed is (x). It takes (4) hours to go (36) kilometres downstream and (24) kilometres upstream. What is (x)?
#quadratic-equations
#word-problems
#boat-stream
A (3)
B (2)
C (5)
D (4)
Explanation opens after your attempt
Step 1
Concept
The equation is \(\frac{36}{15+x}+\frac{24}{15-x}=4\). Substituting (x=3) gives time (2+2=4) hours.
Step 2
Why this answer is correct
The correct answer is A. (3). The equation is \(\frac{36}{15+x}+\frac{24}{15-x}=4\). Substituting (x=3) gives time (2+2=4) hours.
Step 3
Exam Tip
समीकरण \(\frac{36}{15+x}+\frac{24}{15-x}=4\) है। (x=3) रखने पर समय (2+2=4) घंटे मिलता है।
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एक व्यक्ति (240) किलोमीटर यात्रा करता है। गति (20) किलोमीटर प्रति घंटा कम करने पर समय (2) घंटे बढ़ जाता है। मूल गति क्या है?
A person travels (240) kilometres. If the speed is reduced by (20) kilometres per hour, the time increases by (2) hours. What is the original speed?
#quadratic-equations
#word-problems
#speed-change
A (60)
B (40)
C (80)
D (30)
Explanation opens after your attempt
Step 1
Concept
Let the original speed be (x), then \(\frac{240}{x-20}-\frac{240}{x}=2\). Solving gives (x=60).
Step 2
Why this answer is correct
The correct answer is A. (60). Let the original speed be (x), then \(\frac{240}{x-20}-\frac{240}{x}=2\). Solving gives (x=60).
Step 3
Exam Tip
मूल गति (x) हो, तो \(\frac{240}{x-20}-\frac{240}{x}=2\)। हल करने पर (x=60) मिलता है।
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एक ट्रेन (300) किलोमीटर दूरी तय करती है। गति (10) किलोमीटर प्रति घंटा बढ़ाने पर समय (1) घंटा कम हो जाता है। मूल गति क्या है?
A train covers (300) kilometres. If its speed is increased by (10) kilometres per hour, the time decreases by (1) hour. What is the original speed?
#quadratic-equations
#word-problems
#speed-time
A (50)
B (60)
C (40)
D (30)
Explanation opens after your attempt
Step 1
Concept
Let the original speed be (x), then \(\frac{300}{x}-\frac{300}{x+10}=1\). This gives (x=50).
Step 2
Why this answer is correct
The correct answer is A. (50). Let the original speed be (x), then \(\frac{300}{x}-\frac{300}{x+10}=1\). This gives (x=50).
Step 3
Exam Tip
मूल गति (x) हो, तो \(\frac{300}{x}-\frac{300}{x+10}=1\)। इससे (x=50) मिलता है।
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एक वाहन समान समयांतरालों में (18,30,42,54) किलोमीटर चलता है। दूरी अनुक्रम का सामान्य अंतर क्या है?
A vehicle covers (18,30,42,54) kilometres in equal time intervals. What is the common difference of the distance sequence?
#ap
#word_problem
#distance
A (10) किलोमीटर / (10) kilometres
B (12) किलोमीटर / (12) kilometres
C (18) किलोमीटर / (18) kilometres
D (24) किलोमीटर / (24) kilometres
Explanation opens after your attempt
Correct Answer
B. (12) किलोमीटर / (12) kilometres
Step 1
Concept
The distance increases by (12) kilometres each time. In word problems, still find the same consecutive difference.
Step 2
Why this answer is correct
The correct answer is B. (12) किलोमीटर / (12) kilometres. The distance increases by (12) kilometres each time. In word problems, still find the same consecutive difference.
Step 3
Exam Tip
हर बार दूरी (12) किलोमीटर बढ़ती है। परीक्षा में वास्तविक जीवन प्रश्न में भी वही लगातार अंतर निकालें।
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एक टैक्सी सेवा में पहले किलोमीटर का किराया (130) रुपये है और हर अगले किलोमीटर का किराया (40) रुपये अधिक है। (10) किलोमीटर का कुल किराया कितना होगा?
In a taxi service the fare for the first kilometre is (130) rupees and each next kilometre costs (40) rupees more. What is the total fare for (10) kilometres?
#ap
#word-problem
#taxi
#total
A (3000)
B (3100)
C (3200)
D (3300)
Explanation opens after your attempt
Step 1
Concept
The fares form the AP \(130,170,210,\ldots\) and \(S_{10}=3100\). Exam tip: treat each kilometre's fare as one term.
Step 2
Why this answer is correct
The correct answer is B. (3100). The fares form the AP \(130,170,210,\ldots\) and \(S_{10}=3100\). Exam tip: treat each kilometre's fare as one term.
Step 3
Exam Tip
किराया \(130,170,210,\ldots\) समान्तर श्रेणी है और \(S_{10}=3100\)। परीक्षा में हर किलोमीटर का किराया एक पद मानें।
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एक टैक्सी में पहले किलोमीटर का किराया (120) रुपये है और हर अगले किलोमीटर का किराया (35) रुपये अधिक है। (12) किलोमीटर का कुल किराया कितना होगा?
In a taxi the fare for the first kilometre is (120) rupees and each next kilometre costs (35) rupees more. What is the total fare for (12) kilometres?
#ap
#word-problem
#taxi
#fare
A (3650)
B (3700)
C (3750)
D (3800)
Explanation opens after your attempt
Step 1
Concept
The fares are \(120,155,190,\ldots\) and \(S_{12}=3750\). Exam tip: treat each kilometre's fare as one term.
Step 2
Why this answer is correct
The correct answer is C. (3750). The fares are \(120,155,190,\ldots\) and \(S_{12}=3750\). Exam tip: treat each kilometre's fare as one term.
Step 3
Exam Tip
किराया \(120,155,190,\ldots\) है और \(S_{12}=3750\)। परीक्षा में प्रत्येक किलोमीटर का किराया एक पद मानें।
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एक टैक्सी में पहले किलोमीटर का किराया (85) रुपये है और हर अगले किलोमीटर का किराया (30) रुपये अधिक है। (11) किलोमीटर का कुल किराया कितना होगा?
In a taxi the fare for the first kilometre is (85) rupees and each next kilometre costs (30) rupees more. What is the total fare for (11) kilometres?
#ap
#word-problem
#taxi
#total
A (2525)
B (2585)
C (2645)
D (2705)
Explanation opens after your attempt
Step 1
Concept
The fares form the AP \(85,115,145,\ldots\) and \(S_{11}=2585\). Exam tip: treat each kilometre's fare as one term.
Step 2
Why this answer is correct
The correct answer is B. (2585). The fares form the AP \(85,115,145,\ldots\) and \(S_{11}=2585\). Exam tip: treat each kilometre's fare as one term.
Step 3
Exam Tip
किराया \(85,115,145,\ldots\) समान्तर श्रेणी है और \(S_{11}=2585\)। परीक्षा में प्रत्येक किलोमीटर का किराया एक पद मानें।
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एक टैक्सी में पहले किलोमीटर का किराया (100) रुपये है और हर अगले किलोमीटर का किराया (25) रुपये अधिक है। (9) किलोमीटर का कुल किराया कितना होगा?
In a taxi the fare for the first kilometre is (100) rupees and each next kilometre costs (25) rupees more. What is the total fare for (9) kilometres?
#ap
#word-problem
#taxi
#fare
A (1800)
B (1850)
C (1900)
D (1950)
Explanation opens after your attempt
Step 1
Concept
The fares are \(100,125,150,\ldots\) and \(S_9=1800\). Exam tip: treat the fare for each kilometre as one term.
Step 2
Why this answer is correct
The correct answer is A. (1800). The fares are \(100,125,150,\ldots\) and \(S_9=1800\). Exam tip: treat the fare for each kilometre as one term.
Step 3
Exam Tip
किराया \(100,125,150,\ldots\) है और \(S_9=1800\)। परीक्षा में प्रत्येक किलोमीटर का किराया एक पद मानें।
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एक टैक्सी में पहले किलोमीटर का किराया (60) रुपये है और हर अगले किलोमीटर का किराया (18) रुपये अधिक है। (12) किलोमीटर का कुल किराया कितना होगा?
In a taxi the fare for the first kilometre is (60) rupees and each next kilometre costs (18) rupees more. What is the total fare for (12) kilometres?
#ap
#word-problem
#taxi
#fare
A (1848)
B (1908)
C (1968)
D (2028)
Explanation opens after your attempt
Step 1
Concept
The fares are \(60,78,96,\ldots\) and \(S_{12}=1908\). Exam tip: treat the fare for each kilometre as one term.
Step 2
Why this answer is correct
The correct answer is B. (1908). The fares are \(60,78,96,\ldots\) and \(S_{12}=1908\). Exam tip: treat the fare for each kilometre as one term.
Step 3
Exam Tip
किराया \(60,78,96,\ldots\) है और \(S_{12}=1908\)। परीक्षा में प्रत्येक किलोमीटर का किराया एक पद मानें।
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एक टैक्सी में पहले किलोमीटर का किराया (80) रुपये है और हर अगले किलोमीटर का किराया (20) रुपये अधिक है। (10) किलोमीटर का कुल किराया कितना होगा?
In a taxi the fare for the first kilometre is (80) rupees and each next kilometre costs (20) rupees more. What is the total fare for (10) kilometres?
#ap
#word-problem
#taxi-fare
A (1600)
B (1700)
C (1800)
D (1900)
Explanation opens after your attempt
Step 1
Concept
The fares are \(80,100,120,\ldots\), and \(S_{10}=1700\). Exam tip: treat the fare for each kilometre as one term.
Step 2
Why this answer is correct
The correct answer is B. (1700). The fares are \(80,100,120,\ldots\), and \(S_{10}=1700\). Exam tip: treat the fare for each kilometre as one term.
Step 3
Exam Tip
किराया \(80,100,120,\ldots\) है और \(S_{10}=1700\)। परीक्षा में प्रत्येक किलोमीटर का किराया एक पद मानें।
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एक टैक्सी में पहले किलोमीटर का किराया (75) रुपये है और हर अगले किलोमीटर का किराया (12) रुपये अधिक है। (10) किलोमीटर का कुल किराया कितना होगा?
In a taxi the fare for the first kilometre is (75) rupees and each next kilometre costs (12) rupees more. What is the total fare for (10) kilometres?
#ap
#word-problem
#taxi
A (1250)
B (1270)
C (1290)
D (1310)
Explanation opens after your attempt
Step 1
Concept
The fares are \(75,87,99,\ldots\) and \(S_{10}=1290\). Exam tip: treat the fare for each kilometre as one term.
Step 2
Why this answer is correct
The correct answer is C. (1290). The fares are \(75,87,99,\ldots\) and \(S_{10}=1290\). Exam tip: treat the fare for each kilometre as one term.
Step 3
Exam Tip
किराया \(75,87,99,\ldots\) है और \(S_{10}=1290\)। परीक्षा में प्रत्येक किलोमीटर का किराया एक पद मानें।
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एक टैक्सी में पहले किलोमीटर का किराया (60) रुपये है और हर अगले किलोमीटर का किराया (10) रुपये अधिक है। (9) किलोमीटर का कुल किराया कितना होगा?
In a taxi the fare for the first kilometre is (60) rupees and each next kilometre costs (10) rupees more. What is the total fare for (9) kilometres?
#ap
#word-problem
#taxi
A (860)
B (900)
C (940)
D (980)
Explanation opens after your attempt
Step 1
Concept
The fares are \(60,70,80,\ldots\) and \(S_9=900\). Exam tip: treat the fare for each kilometre as one term.
Step 2
Why this answer is correct
The correct answer is B. (900). The fares are \(60,70,80,\ldots\) and \(S_9=900\). Exam tip: treat the fare for each kilometre as one term.
Step 3
Exam Tip
किराया \(60,70,80,\ldots\) है और \(S_9=900\)। परीक्षा में प्रत्येक किलोमीटर का किराया एक पद मानें।
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एक टैक्सी में पहले किलोमीटर का किराया (50) रुपये है और हर अगले किलोमीटर का किराया (15) रुपये अधिक है। (8) किलोमीटर का कुल किराया कितना होगा?
In a taxi the fare for the first kilometre is (50) rupees and each next kilometre costs (15) rupees more. What is the total fare for (8) kilometres?
#ap
#word-problem
#taxi
A (760)
B (790)
C (820)
D (850)
Explanation opens after your attempt
Step 1
Concept
The fares are \(50,65,80,\ldots\) and \(S_8=820\). Exam tip: treat the fare for each kilometre as one term.
Step 2
Why this answer is correct
The correct answer is C. (820). The fares are \(50,65,80,\ldots\) and \(S_8=820\). Exam tip: treat the fare for each kilometre as one term.
Step 3
Exam Tip
किराया \(50,65,80,\ldots\) है और \(S_8=820\)। परीक्षा में प्रत्येक किलोमीटर का किराया एक पद मानें।
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