Topic Quiz • 150 questions • 40 seconds per question.
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What is the slope of the line (y=2x+5)?
A. (2)
In (y=mx+c), (m) is the slope. Here (m=2).
The correct answer is A. (2). In (y=mx+c), (m) is the slope. Here (m=2).
(y=mx+c) में (m) ढाल होता है। यहां (m=2) है।
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What is the (y)-intercept of the line (y=3x-4)?
B. (-4)
In (y=mx+c), (c) is the (y)-intercept. Here (c=-4).
The correct answer is B. (-4). In (y=mx+c), (c) is the (y)-intercept. Here (c=-4).
(y=mx+c) में (c) (y)-अवरोध होता है। यहां (c=-4) है।
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What is the slope of the line (y=-x+7)?
C. (-1)
The coefficient of (x) is the slope. In (y=-x+7), the coefficient of (x) is (-1).
The correct answer is C. (-1). The coefficient of (x) is the slope. In (y=-x+7), the coefficient of (x) is (-1).
(x) का गुणांक ढाल होता है। (y=-x+7) में (x) का गुणांक (-1) है।
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What is the slope of the line (y=8-2x)?
D. (-2)
It can be written as (y=-2x+8). Therefore the slope is (-2).
The correct answer is D. (-2). It can be written as (y=-2x+8). Therefore the slope is (-2).
इसे (y=-2x+8) लिखा जा सकता है। इसलिए ढाल (-2) है।
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What is the (y)-intercept of the line (y=x+9)?
A. (9)
Putting (x=0) gives (y=9). So the (y)-intercept is (9).
The correct answer is A. (9). Putting (x=0) gives (y=9). So the (y)-intercept is (9).
(x=0) रखने पर (y=9) मिलता है। इसलिए (y)-अवरोध (9) है।
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What is the slope of the line (y=5x)?
B. (5)
In (y=5x), the coefficient of (x) is (5). That is the slope.
The correct answer is B. (5). In (y=5x), the coefficient of (x) is (5). That is the slope.
(y=5x) में (x) का गुणांक (5) है। यही ढाल है।
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What is the (y)-intercept of the line (y=-6)?
C. (-6)
Even at (x=0), (y=-6). Therefore the (y)-intercept is (-6).
The correct answer is C. (-6). Even at (x=0), (y=-6). Therefore the (y)-intercept is (-6).
(x=0) पर भी (y=-6) ही रहता है। इसलिए (y)-अवरोध (-6) है।
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In the form (y=mx+c), what does (m) represent?
D. ढालSlope
In the form (y=mx+c), (m) represents the slope. In exams, look at the coefficient of (x).
The correct answer is D. ढाल / Slope. In the form (y=mx+c), (m) represents the slope. In exams, look at the coefficient of (x).
रूप (y=mx+c) में (m) रेखा की ढाल बताता है। परीक्षा में (x) के गुणांक को देखें।
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In the form (y=mx+c), what does (c) represent?
A. (y)-अवरोध(y)-intercept
(c) is the value when (x=0). Therefore (c) is the (y)-intercept.
The correct answer is A. (y)-अवरोध / (y)-intercept. (c) is the value when (x=0). Therefore (c) is the (y)-intercept.
(c) वह मान है जब (x=0) होता है। इसलिए (c) (y)-अवरोध है।
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Which line has slope (4) and (y)-intercept (1)?
B. (y=4x+1)
The slope is the coefficient of (x), and the (y)-intercept is the constant term. So (y=4x+1) is correct.
The correct answer is B. (y=4x+1). The slope is the coefficient of (x), and the (y)-intercept is the constant term. So (y=4x+1) is correct.
ढाल (x) का गुणांक और (y)-अवरोध स्थिर पद होता है। इसलिए (y=4x+1) सही है।
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Which line has slope (-3) and (y)-intercept (2)?
C. (y=-3x+2)
For slope (-3), the coefficient of (x) must be (-3). With (y)-intercept (2), the correct line is (y=-3x+2).
The correct answer is C. (y=-3x+2). For slope (-3), the coefficient of (x) must be (-3). With (y)-intercept (2), the correct line is (y=-3x+2).
ढाल (-3) के लिए (x) का गुणांक (-3) होना चाहिए। (y)-अवरोध (2) होने से सही रेखा (y=-3x+2) है।
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What is the (y)-intercept of the line (y=7x+0)?
D. (0)
The constant term is (0). So the line passes through the origin.
The correct answer is D. (0). The constant term is (0). So the line passes through the origin.
स्थिर पद (0) है। इसलिए रेखा मूल बिंदु से गुजरती है।
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What is the slope of the line (y=0x+11)?
A. (0)
The coefficient of (x) is (0). Therefore the slope of the line is (0).
The correct answer is A. (0). The coefficient of (x) is (0). Therefore the slope of the line is (0).
(x) का गुणांक (0) है। इसलिए रेखा की ढाल (0) है।
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What is the slope of the line (y=-5x-8)?
B. (-5)
The slope equals the coefficient of (x). Here the coefficient of (x) is (-5).
The correct answer is B. (-5). The slope equals the coefficient of (x). Here the coefficient of (x) is (-5).
ढाल (x) के गुणांक के बराबर होती है। यहां (x) का गुणांक (-5) है।
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What is the (y)-intercept of the line (y=12+4x)?
C. (12)
It can be written as (y=4x+12). The constant term is (12).
The correct answer is C. (12). It can be written as (y=4x+12). The constant term is (12).
इसे (y=4x+12) लिख सकते हैं। स्थिर पद (12) है।
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What is the (y)-intercept of the line (y=6-3x)?
D. (6)
Putting (x=0) gives (y=6). Therefore the (y)-intercept is (6).
The correct answer is D. (6). Putting (x=0) gives (y=6). Therefore the (y)-intercept is (6).
(x=0) रखने पर (y=6) मिलता है। इसलिए (y)-अवरोध (6) है।
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In the line (y=-2x+10), what are the slope and (y)-intercept?
A. ढाल (-2), (y)-अवरोध (10)Slope (-2), (y)-intercept (10)
The coefficient of (x) is (-2), and the constant term is (10). These are the slope and (y)-intercept.
The correct answer is A. ढाल (-2), (y)-अवरोध (10) / Slope (-2), (y)-intercept (10). The coefficient of (x) is (-2), and the constant term is (10). These are the slope and (y)-intercept.
(x) का गुणांक (-2) है और स्थिर पद (10) है। यही ढाल और (y)-अवरोध हैं।
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In the line (y=9x-1), what are the slope and (y)-intercept?
B. ढाल (9), (y)-अवरोध (-1)Slope (9), (y)-intercept (-1)
From (y=mx+c), (m=9) and (c=-1). So the slope is (9) and the (y)-intercept is (-1).
The correct answer is B. ढाल (9), (y)-अवरोध (-1) / Slope (9), (y)-intercept (-1). From (y=mx+c), (m=9) and (c=-1). So the slope is (9) and the (y)-intercept is (-1).
(y=mx+c) से (m=9) और (c=-1) है। इसलिए ढाल (9) और (y)-अवरोध (-1) हैं।
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What is the slope of the line \(y=\frac{1}{2}x+3\)?
C. \(\frac{1}{2}\)
The slope equals the coefficient of (x). Here the coefficient is \(\frac{1}{2}\).
The correct answer is C. \(\frac{1}{2}\). The slope equals the coefficient of (x). Here the coefficient is \(\frac{1}{2}\).
ढाल (x) के गुणांक के बराबर होती है। यहां गुणांक \(\frac{1}{2}\) है।
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What is the (y)-intercept of the line \(y=-\frac{3}{4}x+2\)?
B. (2)
The constant term is (2). Therefore the (y)-intercept is (2).
The correct answer is B. (2). The constant term is (2). Therefore the (y)-intercept is (2).
स्थिर पद (2) है। इसलिए (y)-अवरोध (2) है।
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If a line has a positive slope, what generally happens to (y) as (x) increases?
B. (y) बढ़ता है(y) increases
A positive slope shows an increasing line. So as (x) increases, (y) increases.
The correct answer is B. (y) बढ़ता है / (y) increases. A positive slope shows an increasing line. So as (x) increases, (y) increases.
धनात्मक ढाल बढ़ती हुई रेखा दिखाती है। इसलिए (x) बढ़ने पर (y) बढ़ता है।
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If a line has a negative slope, what generally happens to (y) as (x) increases?
C. (y) घटता है(y) decreases
A negative slope shows a decreasing line. So as (x) increases, (y) decreases.
The correct answer is C. (y) घटता है / (y) decreases. A negative slope shows a decreasing line. So as (x) increases, (y) decreases.
ऋणात्मक ढाल घटती हुई रेखा दिखाती है। इसलिए (x) बढ़ने पर (y) घटता है।
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Which can be a general form of a line with slope (0)?
A. (y=5)
When the slope is (0), the coefficient of (x) is (0). (y=5) is a horizontal line.
The correct answer is A. (y=5). When the slope is (0), the coefficient of (x) is (0). (y=5) is a horizontal line.
ढाल (0) होने पर (x) का गुणांक (0) होता है। (y=5) एक क्षैतिज रेखा है।
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Which line passes through the origin?
C. (y=4x)
To pass through the origin, the (y)-intercept must be (0). In (y=4x), the constant term is (0).
The correct answer is C. (y=4x). To pass through the origin, the (y)-intercept must be (0). In (y=4x), the constant term is (0).
मूल बिंदु से गुजरने के लिए (y)-अवरोध (0) होना चाहिए। (y=4x) में स्थिर पद (0) है।
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At which point does the line (y=2x+6) cut the (y)-axis?
D. \((0,6)\)
On the (y)-axis, (x=0). Therefore the point is ((0,6)).
The correct answer is D. \((0,6)\). On the (y)-axis, (x=0). Therefore the point is ((0,6)).
(y)-अक्ष पर (x=0) होता है। इसलिए बिंदु ((0,6)) है।
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At which point does the line (y=-4x+3) cut the (y)-axis?
A. \((0,3)\)
Putting (x=0) gives (y=3). So the point on the (y)-axis is ((0,3)).
The correct answer is A. \((0,3)\). Putting (x=0) gives (y=3). So the point on the (y)-axis is ((0,3)).
(x=0) रखने पर (y=3) मिलता है। इसलिए (y)-अक्ष पर बिंदु ((0,3)) है।
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In the line (y=10x+4), by how much does (y) increase when (x) increases by (1)?
B. (10)
The slope is (10). It means (y) increases by (10) when (x) increases by (1).
The correct answer is B. (10). The slope is (10). It means (y) increases by (10) when (x) increases by (1).
ढाल (10) है। इसका अर्थ है कि (x) के (1) बढ़ने पर (y) (10) बढ़ता है।
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In the line (y=-7x+20), what change occurs in (y) when (x) increases by (1)?
C. (7) घटता हैDecreases by (7)
The slope is (-7). So when (x) increases by (1), (y) decreases by (7).
The correct answer is C. (7) घटता है / Decreases by (7). The slope is (-7). So when (x) increases by (1), (y) decreases by (7).
ढाल (-7) है। इसलिए (x) के (1) बढ़ने पर (y) (7) घटता है।
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What is the constant term in the line (y=4x-9)?
C. (-9)
The constant term is the part without (x). Here the constant term is (-9).
The correct answer is C. (-9). The constant term is the part without (x). Here the constant term is (-9).
स्थिर पद वह भाग है जिसमें (x) नहीं होता। यहां स्थिर पद (-9) है।
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What is the coefficient of (x) in the line (y=-8x+13)?
D. (-8)
The coefficient of (x) is (-8). This is also the slope of the line.
The correct answer is D. (-8). The coefficient of (x) is (-8). This is also the slope of the line.
(x) का गुणांक (-8) है। यही रेखा की ढाल भी है।
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Which line has (y)-intercept (5)?
B. (y=2x+5)
The (y)-intercept is the constant term. In (y=2x+5), the constant term is (5).
The correct answer is B. (y=2x+5). The (y)-intercept is the constant term. In (y=2x+5), the constant term is (5).
(y)-अवरोध स्थिर पद होता है। (y=2x+5) में स्थिर पद (5) है।
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A. (y=-4x+1)
The slope equals the coefficient of (x). In (y=-4x+1), the coefficient is (-4).
The correct answer is A. (y=-4x+1). The slope equals the coefficient of (x). In (y=-4x+1), the coefficient is (-4).
ढाल (x) के गुणांक के बराबर होती है। (y=-4x+1) में गुणांक (-4) है।
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In the line (y=15-5x), what are the slope and (y)-intercept?
C. ढाल (-5), (y)-अवरोध (15)Slope (-5), (y)-intercept (15)
Write it as (y=-5x+15). Therefore the slope is (-5) and the (y)-intercept is (15).
The correct answer is C. ढाल (-5), (y)-अवरोध (15) / Slope (-5), (y)-intercept (15). Write it as (y=-5x+15). Therefore the slope is (-5) and the (y)-intercept is (15).
इसे (y=-5x+15) लिखें। इसलिए ढाल (-5) और (y)-अवरोध (15) है।
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In the line (y=2-9x), what are the slope and (y)-intercept?
A. ढाल (-9), (y)-अवरोध (2)Slope (-9), (y)-intercept (2)
We write (y=2-9x) as (y=-9x+2). So the slope is (-9) and the (y)-intercept is (2).
The correct answer is A. ढाल (-9), (y)-अवरोध (2) / Slope (-9), (y)-intercept (2). We write (y=2-9x) as (y=-9x+2). So the slope is (-9) and the (y)-intercept is (2).
(y=2-9x) को (y=-9x+2) लिखते हैं। इसलिए ढाल (-9) और (y)-अवरोध (2) है।
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If the line (y=mx+6) has (y)-intercept (6), what does (m) represent?
A. ढालSlope
In the form (y=mx+c), (m) always represents the slope. Here (6) is the (y)-intercept.
The correct answer is A. ढाल / Slope. In the form (y=mx+c), (m) always represents the slope. Here (6) is the (y)-intercept.
रूप (y=mx+c) में (m) हमेशा ढाल बताता है। यहां (6) (y)-अवरोध है।
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If the line (y=4x+c) has slope (4), what does (c) represent?
C. (y)-अवरोध(y)-intercept
(c) is the constant term. At (x=0), it becomes the (y)-intercept.
The correct answer is C. (y)-अवरोध / (y)-intercept. (c) is the constant term. At (x=0), it becomes the (y)-intercept.
(c) स्थिर पद है। (x=0) पर यही (y)-अवरोध बनता है।
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What is the (y)-intercept of the line (y=-x-3)?
D. (-3)
The constant term is (-3). Therefore the (y)-intercept is (-3).
The correct answer is D. (-3). The constant term is (-3). Therefore the (y)-intercept is (-3).
स्थिर पद (-3) है। इसलिए (y)-अवरोध (-3) है।
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What is the slope of the line (y=13x+8)?
A. (13)
The slope equals the coefficient of (x). Here the coefficient is (13).
The correct answer is A. (13). The slope equals the coefficient of (x). Here the coefficient is (13).
ढाल (x) के गुणांक के बराबर होती है। यहां गुणांक (13) है।
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What is the slope of the line (y=4)?
B. (0)
(y=4) is a horizontal line. The slope of a horizontal line is (0).
The correct answer is B. (0). (y=4) is a horizontal line. The slope of a horizontal line is (0).
(y=4) एक क्षैतिज रेखा है। क्षैतिज रेखा की ढाल (0) होती है।
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If the line (y=mx+c) cuts the (y)-axis at ((0,7)), what is (c)?
C. (7)
The (y)-value of the point on the (y)-axis is the (y)-intercept. Therefore (c=7).
The correct answer is C. (7). The (y)-value of the point on the (y)-axis is the (y)-intercept. Therefore (c=7).
(y)-अक्ष पर बिंदु का (y)-मान (y)-अवरोध होता है। इसलिए (c=7) है।
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If the line (y=mx+c) cuts the (y)-axis at ((0,-2)), what is (c)?
B. (-2)
On the (y)-axis, (x=0), and the (y)-value is (c). Therefore (c=-2).
The correct answer is B. (-2). On the (y)-axis, (x=0), and the (y)-value is (c). Therefore (c=-2).
(y)-अक्ष पर (x=0) होता है और (y)-मान (c) होता है। इसलिए (c=-2) है।
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Which line has slope (6) and (y)-intercept (-2)?
A. (y=6x-2)
For slope (6), the coefficient of (x) must be (6). With (y)-intercept (-2), the line is (y=6x-2).
The correct answer is A. (y=6x-2). For slope (6), the coefficient of (x) must be (6). With (y)-intercept (-2), the line is (y=6x-2).
ढाल (6) के लिए (x) का गुणांक (6) चाहिए। (y)-अवरोध (-2) से (y=6x-2) बनता है।
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Which line has slope (-1) and (y)-intercept (-5)?
B. (y=-x-5)
Slope (-1) means the coefficient of (x) is (-1). With (y)-intercept (-5), (y=-x-5) is correct.
The correct answer is B. (y=-x-5). Slope (-1) means the coefficient of (x) is (-1). With (y)-intercept (-5), (y=-x-5) is correct.
ढाल (-1) का अर्थ (x) का गुणांक (-1) है। (y)-अवरोध (-5) होने से (y=-x-5) सही है।
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What is the (y)-intercept of the line \(y=\frac{5}{3}x-4\)?
C. (-4)
The constant term is (-4). Therefore the (y)-intercept is (-4).
The correct answer is C. (-4). The constant term is (-4). Therefore the (y)-intercept is (-4).
स्थिर पद (-4) है। इसलिए (y)-अवरोध (-4) है।
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What is the slope of the line \(y=-\frac{2}{5}x+9\)?
B. \(-\frac{2}{5}\)
The slope equals the coefficient of (x). Here the coefficient is \(-\frac{2}{5}\).
The correct answer is B. \(-\frac{2}{5}\). The slope equals the coefficient of (x). Here the coefficient is \(-\frac{2}{5}\).
ढाल (x) के गुणांक के बराबर होती है। यहां गुणांक \(-\frac{2}{5}\) है।
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At what (y)-value does the line (y=3x+12) cut the (y)-axis?
C. (12)
On the (y)-axis, (x=0). Then (y=12).
The correct answer is C. (12). On the (y)-axis, (x=0). Then (y=12).
(y)-अक्ष पर (x=0) होता है। तब (y=12) मिलता है।
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What is the sign of the slope of the line (y=-6x+18)?
C. ऋणात्मकNegative
The slope is (-6). Therefore its sign is negative.
The correct answer is C. ऋणात्मक / Negative. The slope is (-6). Therefore its sign is negative.
ढाल (-6) है। इसलिए उसका चिन्ह ऋणात्मक है।
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What is the sign of the slope of the line (y=11x-7)?
A. धनात्मकPositive
The slope is (11). Therefore its sign is positive.
The correct answer is A. धनात्मक / Positive. The slope is (11). Therefore its sign is positive.
ढाल (11) है। इसलिए उसका चिन्ह धनात्मक है।
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In the line (y=0x-10), what are the slope and (y)-intercept?
A. ढाल (0), (y)-अवरोध (-10)Slope (0), (y)-intercept (-10)
The coefficient of (x) is (0), and the constant term is (-10). So the slope is (0) and the (y)-intercept is (-10).
The correct answer is A. ढाल (0), (y)-अवरोध (-10) / Slope (0), (y)-intercept (-10). The coefficient of (x) is (0), and the constant term is (-10). So the slope is (0) and the (y)-intercept is (-10).
(x) का गुणांक (0) है और स्थिर पद (-10) है। इसलिए ढाल (0) और (y)-अवरोध (-10) है।
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In the line (y=14-2x), what are the coefficient of (x) and the constant term?
C. गुणांक (-2), स्थिर पद (14)Coefficient (-2), constant term (14)
We write it as (y=-2x+14). Therefore the coefficient of (x) is (-2), and the constant term is (14).
The correct answer is C. गुणांक (-2), स्थिर पद (14) / Coefficient (-2), constant term (14). We write it as (y=-2x+14). Therefore the coefficient of (x) is (-2), and the constant term is (14).
इसे (y=-2x+14) लिखते हैं। इसलिए (x) का गुणांक (-2) और स्थिर पद (14) है।
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What is the slope of the line (y=4x+3)?
A. (4)
In (y=mx+c), (m) is the slope. Here (m=4).
The correct answer is A. (4). In (y=mx+c), (m) is the slope. Here (m=4).
(y=mx+c) में (m) ढाल होता है। यहां (m=4) है।
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What is the (y)-intercept of the line (y=5x-6)?
B. (-6)
In (y=mx+c), (c) is the (y)-intercept. Here (c=-6).
The correct answer is B. (-6). In (y=mx+c), (c) is the (y)-intercept. Here (c=-6).
(y=mx+c) में (c) (y)-अवरोध होता है। यहां (c=-6) है।
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What is the slope of the line (y=-3x+8)?
C. (-3)
The slope equals the coefficient of (x). Here the coefficient is (-3).
The correct answer is C. (-3). The slope equals the coefficient of (x). Here the coefficient is (-3).
ढाल (x) के गुणांक के बराबर होती है। यहां गुणांक (-3) है।
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What is the slope of the line (y=11-4x)?
D. (-4)
It can be written as (y=-4x+11). Therefore the slope is (-4).
The correct answer is D. (-4). It can be written as (y=-4x+11). Therefore the slope is (-4).
इसे (y=-4x+11) लिखा जा सकता है। इसलिए ढाल (-4) है।
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What is the (y)-intercept of the line (y=2x+9)?
A. (9)
Putting (x=0) gives (y=9). Therefore the (y)-intercept is (9).
The correct answer is A. (9). Putting (x=0) gives (y=9). Therefore the (y)-intercept is (9).
(x=0) रखने पर (y=9) मिलता है। इसलिए (y)-अवरोध (9) है।
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What is the slope of the line (y=-7x+1)?
B. (-7)
The coefficient of (x) is (-7). This is the slope of the line.
The correct answer is B. (-7). The coefficient of (x) is (-7). This is the slope of the line.
(x) का गुणांक (-7) है। यही रेखा की ढाल है।
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What is the slope of the line (y=0x+14)?
D. (0)
The coefficient of (x) is (0). Therefore the slope of the line is (0).
The correct answer is D. (0). The coefficient of (x) is (0). Therefore the slope of the line is (0).
(x) का गुणांक (0) है। इसलिए रेखा की ढाल (0) है।
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In the form (y=mx+c), how is the slope identified?
A. (x) के गुणांक (m) सेBy the coefficient (m) of (x)
The slope is found from the coefficient of (x). In exams, identify (m) directly.
The correct answer is A. (x) के गुणांक (m) से / By the coefficient (m) of (x). The slope is found from the coefficient of (x). In exams, identify (m) directly.
ढाल (x) के गुणांक से मिलती है। परीक्षा में (m) को सीधे पहचानें।
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In the form (y=mx+c), how is the (y)-intercept identified?
B. स्थिर पद (c) सेBy constant term (c)
The (y)-intercept is the constant term (c). It gives the value of (y) at (x=0).
The correct answer is B. स्थिर पद (c) से / By constant term (c). The (y)-intercept is the constant term (c). It gives the value of (y) at (x=0).
(y)-अवरोध स्थिर पद (c) होता है। यह (x=0) पर (y) का मान देता है।
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Which line has slope (5) and (y)-intercept (2)?
C. (y=5x+2)
For slope (5), the coefficient of (x) must be (5). With (y)-intercept (2), (y=5x+2) is correct.
The correct answer is C. (y=5x+2). For slope (5), the coefficient of (x) must be (5). With (y)-intercept (2), (y=5x+2) is correct.
ढाल (5) के लिए (x) का गुणांक (5) चाहिए। (y)-अवरोध (2) होने से (y=5x+2) सही है।
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Which line has slope (-2) and (y)-intercept (4)?
D. (y=-2x+4)
We need slope (-2) and constant term (4). Therefore the correct equation is (y=-2x+4).
The correct answer is D. (y=-2x+4). We need slope (-2) and constant term (4). Therefore the correct equation is (y=-2x+4).
ढाल (-2) और स्थिर पद (4) चाहिए। इसलिए सही समीकरण (y=-2x+4) है।
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What is the (y)-intercept of the line (y=9x+0)?
A. (0)
The constant term is (0). Therefore the line passes through the origin.
The correct answer is A. (0). The constant term is (0). Therefore the line passes through the origin.
स्थिर पद (0) है। इसलिए रेखा मूल बिंदु से गुजरती है।
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What is the slope of the line (y=-10x-3)?
B. (-10)
The slope equals the coefficient of (x). Here the coefficient of (x) is (-10).
The correct answer is B. (-10). The slope equals the coefficient of (x). Here the coefficient of (x) is (-10).
ढाल (x) के गुणांक के बराबर होती है। यहां (x) का गुणांक (-10) है।
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What is the (y)-intercept of the line (y=15+6x)?
C. (15)
It can be written as (y=6x+15). The constant term is (15).
The correct answer is C. (15). It can be written as (y=6x+15). The constant term is (15).
इसे (y=6x+15) लिखा जा सकता है। स्थिर पद (15) है।
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In the line (y=20-5x), what are the slope and (y)-intercept?
D. ढाल (-5), (y)-अवरोध (20)Slope (-5), (y)-intercept (20)
Write it as (y=-5x+20). Therefore the slope is (-5) and the (y)-intercept is (20).
The correct answer is D. ढाल (-5), (y)-अवरोध (20) / Slope (-5), (y)-intercept (20). Write it as (y=-5x+20). Therefore the slope is (-5) and the (y)-intercept is (20).
इसे (y=-5x+20) लिखें। इसलिए ढाल (-5) और (y)-अवरोध (20) है।
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In the line (y=3x-8), what are the slope and (y)-intercept?
A. ढाल (3), (y)-अवरोध (-8)Slope (3), (y)-intercept (-8)
From (y=mx+c), (m=3) and (c=-8). These are the slope and the (y)-intercept.
The correct answer is A. ढाल (3), (y)-अवरोध (-8) / Slope (3), (y)-intercept (-8). From (y=mx+c), (m=3) and (c=-8). These are the slope and the (y)-intercept.
(y=mx+c) से (m=3) और (c=-8) है। यही ढाल और (y)-अवरोध हैं।
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In the line (y=-x+12), what are the slope and (y)-intercept?
B. ढाल (-1), (y)-अवरोध (12)Slope (-1), (y)-intercept (12)
The coefficient of (-x) is (-1), and the constant term is (12). So the slope is (-1) and the (y)-intercept is (12).
The correct answer is B. ढाल (-1), (y)-अवरोध (12) / Slope (-1), (y)-intercept (12). The coefficient of (-x) is (-1), and the constant term is (12). So the slope is (-1) and the (y)-intercept is (12).
(-x) का गुणांक (-1) है और स्थिर पद (12) है। इसलिए ढाल (-1) और (y)-अवरोध (12) है।
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What is the slope of the line \(y=\frac{2}{3}x+5\)?
C. \(\frac{2}{3}\)
The slope equals the coefficient of (x). Here the coefficient is \(\frac{2}{3}\).
The correct answer is C. \(\frac{2}{3}\). The slope equals the coefficient of (x). Here the coefficient is \(\frac{2}{3}\).
ढाल (x) के गुणांक के बराबर होती है। यहां गुणांक \(\frac{2}{3}\) है।
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What is the (y)-intercept of the line \(y=-\frac{5}{6}x-2\)?
B. (-2)
The constant term is (-2). Therefore the (y)-intercept is (-2).
The correct answer is B. (-2). The constant term is (-2). Therefore the (y)-intercept is (-2).
स्थिर पद (-2) है। इसलिए (y)-अवरोध (-2) है।
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How does the graph of a line with positive slope generally look?
A. बाएं से दाएं ऊपर जाता हैGoes upward from left to right
With positive slope, (y) increases as (x) increases. So the line goes upward.
The correct answer is A. बाएं से दाएं ऊपर जाता है / Goes upward from left to right. With positive slope, (y) increases as (x) increases. So the line goes upward.
धनात्मक ढाल में (x) बढ़ने पर (y) बढ़ता है। इसलिए रेखा ऊपर की ओर जाती है।
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How does the graph of a line with negative slope generally look?
B. बाएं से दाएं नीचे जाता हैGoes downward from left to right
With negative slope, (y) decreases as (x) increases. So the line goes downward.
The correct answer is B. बाएं से दाएं नीचे जाता है / Goes downward from left to right. With negative slope, (y) decreases as (x) increases. So the line goes downward.
ऋणात्मक ढाल में (x) बढ़ने पर (y) घटता है। इसलिए रेखा नीचे की ओर जाती है।
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Which line can have slope (0)?
C. (y=7)
When the slope is (0), (y) remains constant. (y=7) is a horizontal line.
The correct answer is C. (y=7). When the slope is (0), (y) remains constant. (y=7) is a horizontal line.
ढाल (0) होने पर (y) स्थिर रहता है। (y=7) एक क्षैतिज रेखा है।
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Which line passes through the origin ((0,0))?
D. (y=6x)
To pass through the origin, the (y)-intercept must be (0). In (y=6x), the constant term is (0).
The correct answer is D. (y=6x). To pass through the origin, the (y)-intercept must be (0). In (y=6x), the constant term is (0).
मूल बिंदु से गुजरने के लिए (y)-अवरोध (0) होना चाहिए। (y=6x) में स्थिर पद (0) है।
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At which point does the line (y=4x+10) cut the (y)-axis?
A. ( (0,10) )
On the (y)-axis, (x=0). Therefore the point is ( (0,10) ).
The correct answer is A. ( (0,10) ). On the (y)-axis, (x=0). Therefore the point is ( (0,10) ).
(y)-अक्ष पर (x=0) होता है। इसलिए बिंदु ( (0,10) ) है।
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At which point does the line (y=-5x+7) cut the (y)-axis?
B. ( (0,7) )
Putting (x=0) gives (y=7). So the point on the (y)-axis is ( (0,7) ).
The correct answer is B. ( (0,7) ). Putting (x=0) gives (y=7). So the point on the (y)-axis is ( (0,7) ).
(x=0) रखने पर (y=7) मिलता है। इसलिए (y)-अक्ष पर बिंदु ( (0,7) ) है।
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In the line (y=8x+6), by how much does (y) increase when (x) increases by (1)?
C. (8)
The slope is (8). It means (y) increases by (8) when (x) increases by (1).
The correct answer is C. (8). The slope is (8). It means (y) increases by (8) when (x) increases by (1).
ढाल (8) है। इसका अर्थ है कि (x) के (1) बढ़ने पर (y) (8) बढ़ता है।
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In the line (y=-6x+13), what change occurs in (y) when (x) increases by (1)?
D. (6) घटता हैDecreases by (6)
The slope is (-6). So when (x) increases by (1), (y) decreases by (6).
The correct answer is D. (6) घटता है / Decreases by (6). The slope is (-6). So when (x) increases by (1), (y) decreases by (6).
ढाल (-6) है। इसलिए (x) के (1) बढ़ने पर (y) (6) घटता है।
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What is the constant term in the line (y=7x-11)?
C. (-11)
The constant term is the part without (x). Here the constant term is (-11).
The correct answer is C. (-11). The constant term is the part without (x). Here the constant term is (-11).
स्थिर पद वह भाग है जिसमें (x) नहीं होता। यहां स्थिर पद (-11) है।
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What is the coefficient of (x) in the line (y=-9x+16)?
D. (-9)
The coefficient of (x) is (-9). This is also the slope of the line.
The correct answer is D. (-9). The coefficient of (x) is (-9). This is also the slope of the line.
(x) का गुणांक (-9) है। यही रेखा की ढाल भी है।
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Which line has (y)-intercept (-3)?
B. (y=2x-3)
The (y)-intercept is the constant term. In (y=2x-3), the constant term is (-3).
The correct answer is B. (y=2x-3). The (y)-intercept is the constant term. In (y=2x-3), the constant term is (-3).
(y)-अवरोध स्थिर पद होता है। (y=2x-3) में स्थिर पद (-3) है।
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C. (y=6x-4)
The slope equals the coefficient of (x). In (y=6x-4), the coefficient is (6).
The correct answer is C. (y=6x-4). The slope equals the coefficient of (x). In (y=6x-4), the coefficient is (6).
ढाल (x) के गुणांक के बराबर होती है। (y=6x-4) में गुणांक (6) है।
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In the line (y=18-7x), what are the slope and (y)-intercept?
D. ढाल (-7), (y)-अवरोध (18)Slope (-7), (y)-intercept (18)
We write it as (y=-7x+18). Therefore the slope is (-7) and the (y)-intercept is (18).
The correct answer is D. ढाल (-7), (y)-अवरोध (18) / Slope (-7), (y)-intercept (18). We write it as (y=-7x+18). Therefore the slope is (-7) and the (y)-intercept is (18).
इसे (y=-7x+18) लिखते हैं। इसलिए ढाल (-7) और (y)-अवरोध (18) है।
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In the line (y=5-8x), what are the slope and (y)-intercept?
A. ढाल (-8), (y)-अवरोध (5)Slope (-8), (y)-intercept (5)
We write (y=5-8x) as (y=-8x+5). So the slope is (-8) and the (y)-intercept is (5).
The correct answer is A. ढाल (-8), (y)-अवरोध (5) / Slope (-8), (y)-intercept (5). We write (y=5-8x) as (y=-8x+5). So the slope is (-8) and the (y)-intercept is (5).
(y=5-8x) को (y=-8x+5) लिखते हैं। इसलिए ढाल (-8) और (y)-अवरोध (5) है।
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If the line is (y=mx-4), what does (m) represent?
A. ढालSlope
In the form (y=mx+c), (m) represents the slope. Here (-4) is the (y)-intercept.
The correct answer is A. ढाल / Slope. In the form (y=mx+c), (m) represents the slope. Here (-4) is the (y)-intercept.
रूप (y=mx+c) में (m) ढाल बताता है। यहां (-4) (y)-अवरोध है।
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If the line (y=-3x+c) has slope (-3), what does (c) represent?
C. (y)-अवरोध(y)-intercept
(c) is the constant term. At (x=0), it becomes the (y)-intercept.
The correct answer is C. (y)-अवरोध / (y)-intercept. (c) is the constant term. At (x=0), it becomes the (y)-intercept.
(c) स्थिर पद है। (x=0) पर यही (y)-अवरोध बनता है।
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What is the (y)-intercept of the line (y=-x-9)?
D. (-9)
The constant term is (-9). Therefore the (y)-intercept is (-9).
The correct answer is D. (-9). The constant term is (-9). Therefore the (y)-intercept is (-9).
स्थिर पद (-9) है। इसलिए (y)-अवरोध (-9) है।
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What is the slope of the line (y=15x+2)?
A. (15)
The slope equals the coefficient of (x). Here the coefficient is (15).
The correct answer is A. (15). The slope equals the coefficient of (x). Here the coefficient is (15).
ढाल (x) के गुणांक के बराबर होती है। यहां गुणांक (15) है।
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What is the slope of the line (y=-12)?
B. (0)
(y=-12) is a horizontal line. The slope of a horizontal line is (0).
The correct answer is B. (0). (y=-12) is a horizontal line. The slope of a horizontal line is (0).
(y=-12) एक क्षैतिज रेखा है। क्षैतिज रेखा की ढाल (0) होती है।
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If the line (y=mx+c) cuts the (y)-axis at ((0,4)), what is (c)?
C. (4)
The (y)-value of the point on the (y)-axis is the (y)-intercept. Therefore (c=4).
The correct answer is C. (4). The (y)-value of the point on the (y)-axis is the (y)-intercept. Therefore (c=4).
(y)-अक्ष पर बिंदु का (y)-मान (y)-अवरोध होता है। इसलिए (c=4) है।
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Which line has slope (7) and (y)-intercept (-1)?
A. (y=7x-1)
For slope (7), the coefficient of (x) must be (7). With (y)-intercept (-1), the line is (y=7x-1).
The correct answer is A. (y=7x-1). For slope (7), the coefficient of (x) must be (7). With (y)-intercept (-1), the line is (y=7x-1).
ढाल (7) के लिए (x) का गुणांक (7) चाहिए। (y)-अवरोध (-1) से (y=7x-1) बनता है।
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Which line has slope (-4) and (y)-intercept (-6)?
B. (y=-4x-6)
Slope (-4) means the coefficient of (x) is (-4). With (y)-intercept (-6), (y=-4x-6) is correct.
The correct answer is B. (y=-4x-6). Slope (-4) means the coefficient of (x) is (-4). With (y)-intercept (-6), (y=-4x-6) is correct.
ढाल (-4) का अर्थ (x) का गुणांक (-4) है। (y)-अवरोध (-6) होने से (y=-4x-6) सही है।
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What is the (y)-intercept of the line \(y=\frac{7}{2}x+1\)?
C. (1)
The constant term is (1). Therefore the (y)-intercept is (1).
The correct answer is C. (1). The constant term is (1). Therefore the (y)-intercept is (1).
स्थिर पद (1) है। इसलिए (y)-अवरोध (1) है।
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What is the slope of the line \(y=-\frac{4}{7}x+6\)?
B. \(-\frac{4}{7}\)
The slope equals the coefficient of (x). Here the coefficient is \(-\frac{4}{7}\).
The correct answer is B. \(-\frac{4}{7}\). The slope equals the coefficient of (x). Here the coefficient is \(-\frac{4}{7}\).
ढाल (x) के गुणांक के बराबर होती है। यहां गुणांक \(-\frac{4}{7}\) है।
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At what (y)-value does the line (y=6x+18) cut the (y)-axis?
C. (18)
On the (y)-axis, (x=0). Then (y=18).
The correct answer is C. (18). On the (y)-axis, (x=0). Then (y=18).
(y)-अक्ष पर (x=0) होता है। तब (y=18) मिलता है।
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What is the sign of the slope of the line (y=-8x+25)?
C. ऋणात्मकNegative
The slope is (-8). Therefore its sign is negative.
The correct answer is C. ऋणात्मक / Negative. The slope is (-8). Therefore its sign is negative.
ढाल (-8) है। इसलिए उसका चिन्ह ऋणात्मक है।
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What is the sign of the slope of the line (y=12x-5)?
A. धनात्मकPositive
The slope is (12). Therefore its sign is positive.
The correct answer is A. धनात्मक / Positive. The slope is (12). Therefore its sign is positive.
ढाल (12) है। इसलिए उसका चिन्ह धनात्मक है।
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In the line (y=0x+3), what are the slope and (y)-intercept?
A. ढाल (0), (y)-अवरोध (3)Slope (0), (y)-intercept (3)
The coefficient of (x) is (0), and the constant term is (3). So the slope is (0) and the (y)-intercept is (3).
The correct answer is A. ढाल (0), (y)-अवरोध (3) / Slope (0), (y)-intercept (3). The coefficient of (x) is (0), and the constant term is (3). So the slope is (0) and the (y)-intercept is (3).
(x) का गुणांक (0) है और स्थिर पद (3) है। इसलिए ढाल (0) और (y)-अवरोध (3) है।
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In the line (y=17-6x), what are the coefficient of (x) and the constant term?
C. गुणांक (-6), स्थिर पद (17)Coefficient (-6), constant term (17)
We write it as (y=-6x+17). Therefore the coefficient of (x) is (-6), and the constant term is (17).
The correct answer is C. गुणांक (-6), स्थिर पद (17) / Coefficient (-6), constant term (17). We write it as (y=-6x+17). Therefore the coefficient of (x) is (-6), and the constant term is (17).
इसे (y=-6x+17) लिखते हैं। इसलिए (x) का गुणांक (-6) और स्थिर पद (17) है।
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At which point does the line (y=9-3x) cut the (y)-axis?
A. ( (0,9) )
On the (y)-axis, (x=0). Therefore the point is ( (0,9) ).
The correct answer is A. ( (0,9) ). On the (y)-axis, (x=0). Therefore the point is ( (0,9) ).
(y)-अक्ष पर (x=0) होता है। इसलिए बिंदु ( (0,9) ) है।
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In the line (y=-11x+4), what change occurs in (y) when (x) increases by (1)?
D. (11) घटता हैDecreases by (11)
The slope is (-11). So when (x) increases by (1), (y) decreases by (11).
The correct answer is D. (11) घटता है / Decreases by (11). The slope is (-11). So when (x) increases by (1), (y) decreases by (11).
ढाल (-11) है। इसलिए (x) के (1) बढ़ने पर (y) (11) घटता है।
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What is the slope of the line (y=6x+2)?
A. (6)
In (y=mx+c), (m) is the slope. Here (m=6).
The correct answer is A. (6). In (y=mx+c), (m) is the slope. Here (m=6).
(y=mx+c) में (m) ढाल होता है। यहां (m=6) है।
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What is the (y)-intercept of the line (y=7x-5)?
B. (-5)
In (y=mx+c), (c) is the (y)-intercept. Here (c=-5).
The correct answer is B. (-5). In (y=mx+c), (c) is the (y)-intercept. Here (c=-5).
(y=mx+c) में (c) (y)-अवरोध होता है। यहां (c=-5) है।
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What is the slope of the line (y=-4x+9)?
C. (-4)
The slope equals the coefficient of (x). Here the coefficient is (-4).
The correct answer is C. (-4). The slope equals the coefficient of (x). Here the coefficient is (-4).
ढाल (x) के गुणांक के बराबर होती है। यहां गुणांक (-4) है।
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What is the slope of the line (y=13-5x)?
D. (-5)
It can be written as (y=-5x+13). Therefore the slope is (-5).
The correct answer is D. (-5). It can be written as (y=-5x+13). Therefore the slope is (-5).
इसे (y=-5x+13) लिखा जा सकता है। इसलिए ढाल (-5) है।
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What is the (y)-intercept of the line (y=3x+11)?
A. (11)
Putting (x=0) gives (y=11). Therefore the (y)-intercept is (11).
The correct answer is A. (11). Putting (x=0) gives (y=11). Therefore the (y)-intercept is (11).
(x=0) रखने पर (y=11) मिलता है। इसलिए (y)-अवरोध (11) है।
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What is the slope of the line (y=-9x+4)?
B. (-9)
The coefficient of (x) is (-9). This is the slope of the line.
The correct answer is B. (-9). The coefficient of (x) is (-9). This is the slope of the line.
(x) का गुणांक (-9) है। यही रेखा की ढाल है।
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What is the (y)-intercept of the line (y=8)?
C. (8)
In (y=8), even at (x=0), (y=8). Therefore the (y)-intercept is (8).
The correct answer is C. (8). In (y=8), even at (x=0), (y=8). Therefore the (y)-intercept is (8).
(y=8) में (x=0) पर भी (y=8) रहता है। इसलिए (y)-अवरोध (8) है।
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What is the slope of the line (y=0x+17)?
D. (0)
The coefficient of (x) is (0). Therefore the slope of the line is (0).
The correct answer is D. (0). The coefficient of (x) is (0). Therefore the slope of the line is (0).
(x) का गुणांक (0) है। इसलिए रेखा की ढाल (0) है।
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Which line has slope (8) and (y)-intercept (3)?
C. (y=8x+3)
For slope (8), the coefficient of (x) must be (8). With (y)-intercept (3), (y=8x+3) is correct.
The correct answer is C. (y=8x+3). For slope (8), the coefficient of (x) must be (8). With (y)-intercept (3), (y=8x+3) is correct.
ढाल (8) के लिए (x) का गुणांक (8) चाहिए। (y)-अवरोध (3) होने से (y=8x+3) सही है।
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Which line has slope (-5) and (y)-intercept (6)?
D. (y=-5x+6)
We need slope (-5) and constant term (6). Therefore the correct line is (y=-5x+6).
The correct answer is D. (y=-5x+6). We need slope (-5) and constant term (6). Therefore the correct line is (y=-5x+6).
ढाल (-5) और स्थिर पद (6) चाहिए। इसलिए सही रेखा (y=-5x+6) है।
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What is the (y)-intercept of the line (y=12x+0)?
A. (0)
The constant term is (0). Therefore the line passes through the origin.
The correct answer is A. (0). The constant term is (0). Therefore the line passes through the origin.
स्थिर पद (0) है। इसलिए रेखा मूल बिंदु से गुजरती है।
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What is the slope of the line (y=-11x-2)?
B. (-11)
The slope equals the coefficient of (x). Here the coefficient of (x) is (-11).
The correct answer is B. (-11). The slope equals the coefficient of (x). Here the coefficient of (x) is (-11).
ढाल (x) के गुणांक के बराबर होती है। यहां (x) का गुणांक (-11) है।
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What is the (y)-intercept of the line (y=19+7x)?
C. (19)
It can be written as (y=7x+19). The constant term is (19).
The correct answer is C. (19). It can be written as (y=7x+19). The constant term is (19).
इसे (y=7x+19) लिखा जा सकता है। स्थिर पद (19) है।
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In the line (y=24-6x), what are the slope and (y)-intercept?
D. ढाल (-6), (y)-अवरोध (24)Slope (-6), (y)-intercept (24)
Write it as (y=-6x+24). Therefore the slope is (-6) and the (y)-intercept is (24).
The correct answer is D. ढाल (-6), (y)-अवरोध (24) / Slope (-6), (y)-intercept (24). Write it as (y=-6x+24). Therefore the slope is (-6) and the (y)-intercept is (24).
इसे (y=-6x+24) लिखें। इसलिए ढाल (-6) और (y)-अवरोध (24) है।
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In the line (y=4x-10), what are the slope and (y)-intercept?
A. ढाल (4), (y)-अवरोध (-10)Slope (4), (y)-intercept (-10)
From (y=mx+c), (m=4) and (c=-10). These are the slope and the (y)-intercept.
The correct answer is A. ढाल (4), (y)-अवरोध (-10) / Slope (4), (y)-intercept (-10). From (y=mx+c), (m=4) and (c=-10). These are the slope and the (y)-intercept.
(y=mx+c) से (m=4) और (c=-10) है। यही ढाल और (y)-अवरोध हैं।
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In the line (y=-x+15), what are the slope and (y)-intercept?
B. ढाल (-1), (y)-अवरोध (15)Slope (-1), (y)-intercept (15)
The coefficient of (-x) is (-1), and the constant term is (15). So the slope is (-1) and the (y)-intercept is (15).
The correct answer is B. ढाल (-1), (y)-अवरोध (15) / Slope (-1), (y)-intercept (15). The coefficient of (-x) is (-1), and the constant term is (15). So the slope is (-1) and the (y)-intercept is (15).
(-x) का गुणांक (-1) है और स्थिर पद (15) है। इसलिए ढाल (-1) और (y)-अवरोध (15) है।
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What is the slope of the line \(y=\frac{3}{5}x+7\)?
C. \(\frac{3}{5}\)
The slope equals the coefficient of (x). Here the coefficient is \(\frac{3}{5}\).
The correct answer is C. \(\frac{3}{5}\). The slope equals the coefficient of (x). Here the coefficient is \(\frac{3}{5}\).
ढाल (x) के गुणांक के बराबर होती है। यहां गुणांक \(\frac{3}{5}\) है।
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What is the (y)-intercept of the line \(y=-\frac{7}{8}x-4\)?
B. (-4)
The constant term is (-4). Therefore the (y)-intercept is (-4).
The correct answer is B. (-4). The constant term is (-4). Therefore the (y)-intercept is (-4).
स्थिर पद (-4) है। इसलिए (y)-अवरोध (-4) है।
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In a line with positive slope, what does (y) generally do when (x) increases?
A. बढ़ता हैIncreases
With positive slope, (y) increases as (x) increases. It shows an increasing line.
The correct answer is A. बढ़ता है / Increases. With positive slope, (y) increases as (x) increases. It shows an increasing line.
धनात्मक ढाल में (x) बढ़ने पर (y) बढ़ता है। यह बढ़ती हुई रेखा दिखाता है।
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In a line with negative slope, what does (y) generally do when (x) increases?
B. घटता हैDecreases
With negative slope, (y) decreases as (x) increases. It shows a decreasing line.
The correct answer is B. घटता है / Decreases. With negative slope, (y) decreases as (x) increases. It shows a decreasing line.
ऋणात्मक ढाल में (x) बढ़ने पर (y) घटता है। यह घटती हुई रेखा दिखाता है।
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At which point does the line (y=5x+12) cut the (y)-axis?
A. ( (0,12) )
On the (y)-axis, (x=0). Therefore the point is ( (0,12) ).
The correct answer is A. ( (0,12) ). On the (y)-axis, (x=0). Therefore the point is ( (0,12) ).
(y)-अक्ष पर (x=0) होता है। इसलिए बिंदु ( (0,12) ) है।
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At which point does the line (y=-7x+10) cut the (y)-axis?
B. ( (0,10) )
Putting (x=0) gives (y=10). So the point on the (y)-axis is ( (0,10) ).
The correct answer is B. ( (0,10) ). Putting (x=0) gives (y=10). So the point on the (y)-axis is ( (0,10) ).
(x=0) रखने पर (y=10) मिलता है। इसलिए (y)-अक्ष पर बिंदु ( (0,10) ) है।
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In the line (y=9x+8), by how much does (y) increase when (x) increases by (1)?
C. (9)
The slope is (9). It means (y) increases by (9) when (x) increases by (1).
The correct answer is C. (9). The slope is (9). It means (y) increases by (9) when (x) increases by (1).
ढाल (9) है। इसका अर्थ है कि (x) के (1) बढ़ने पर (y) (9) बढ़ता है।
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In the line (y=-8x+21), what change occurs in (y) when (x) increases by (1)?
D. (8) घटता हैDecreases by (8)
The slope is (-8). So when (x) increases by (1), (y) decreases by (8).
The correct answer is D. (8) घटता है / Decreases by (8). The slope is (-8). So when (x) increases by (1), (y) decreases by (8).
ढाल (-8) है। इसलिए (x) के (1) बढ़ने पर (y) (8) घटता है।
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What is the constant term in the line (y=10x-13)?
C. (-13)
The constant term is the part without (x). Here the constant term is (-13).
The correct answer is C. (-13). The constant term is the part without (x). Here the constant term is (-13).
स्थिर पद वह भाग है जिसमें (x) नहीं होता। यहां स्थिर पद (-13) है।
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What is the coefficient of (x) in the line (y=-12x+18)?
D. (-12)
The coefficient of (x) is (-12). This is also the slope of the line.
The correct answer is D. (-12). The coefficient of (x) is (-12). This is also the slope of the line.
(x) का गुणांक (-12) है। यही रेखा की ढाल भी है।
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Which line has (y)-intercept (-4)?
B. (y=3x-4)
The (y)-intercept is the constant term. In (y=3x-4), the constant term is (-4).
The correct answer is B. (y=3x-4). The (y)-intercept is the constant term. In (y=3x-4), the constant term is (-4).
(y)-अवरोध स्थिर पद होता है। (y=3x-4) में स्थिर पद (-4) है।
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C. (y=7x-6)
The slope equals the coefficient of (x). In (y=7x-6), the coefficient is (7).
The correct answer is C. (y=7x-6). The slope equals the coefficient of (x). In (y=7x-6), the coefficient is (7).
ढाल (x) के गुणांक के बराबर होती है। (y=7x-6) में गुणांक (7) है।
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In the line (y=22-9x), what are the slope and (y)-intercept?
D. ढाल (-9), (y)-अवरोध (22)Slope (-9), (y)-intercept (22)
We write it as (y=-9x+22). Therefore the slope is (-9) and the (y)-intercept is (22).
The correct answer is D. ढाल (-9), (y)-अवरोध (22) / Slope (-9), (y)-intercept (22). We write it as (y=-9x+22). Therefore the slope is (-9) and the (y)-intercept is (22).
इसे (y=-9x+22) लिखते हैं। इसलिए ढाल (-9) और (y)-अवरोध (22) है।
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In the line (y=7-10x), what are the slope and (y)-intercept?
A. ढाल (-10), (y)-अवरोध (7)Slope (-10), (y)-intercept (7)
We write (y=7-10x) as (y=-10x+7). So the slope is (-10) and the (y)-intercept is (7).
The correct answer is A. ढाल (-10), (y)-अवरोध (7) / Slope (-10), (y)-intercept (7). We write (y=7-10x) as (y=-10x+7). So the slope is (-10) and the (y)-intercept is (7).
(y=7-10x) को (y=-10x+7) लिखते हैं। इसलिए ढाल (-10) और (y)-अवरोध (7) है।
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If the line is (y=mx-8), what does (m) represent?
A. ढालSlope
In the form (y=mx+c), (m) represents the slope. Here (-8) is the (y)-intercept.
The correct answer is A. ढाल / Slope. In the form (y=mx+c), (m) represents the slope. Here (-8) is the (y)-intercept.
रूप (y=mx+c) में (m) ढाल बताता है। यहां (-8) (y)-अवरोध है।
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What is the (y)-intercept of the line (y=-x-12)?
D. (-12)
The constant term is (-12). Therefore the (y)-intercept is (-12).
The correct answer is D. (-12). The constant term is (-12). Therefore the (y)-intercept is (-12).
स्थिर पद (-12) है। इसलिए (y)-अवरोध (-12) है।
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What is the slope of the line (y=16x+5)?
A. (16)
The slope equals the coefficient of (x). Here the coefficient is (16).
The correct answer is A. (16). The slope equals the coefficient of (x). Here the coefficient is (16).
ढाल (x) के गुणांक के बराबर होती है। यहां गुणांक (16) है।
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What is the slope of the line (y=-15)?
B. (0)
(y=-15) is a horizontal line. The slope of a horizontal line is (0).
The correct answer is B. (0). (y=-15) is a horizontal line. The slope of a horizontal line is (0).
(y=-15) एक क्षैतिज रेखा है। क्षैतिज रेखा की ढाल (0) होती है।
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If the line (y=mx+c) cuts the (y)-axis at ( (0,6) ), what is (c)?
C. (6)
The (y)-value of the point on the (y)-axis is the (y)-intercept. Therefore (c=6).
The correct answer is C. (6). The (y)-value of the point on the (y)-axis is the (y)-intercept. Therefore (c=6).
(y)-अक्ष पर बिंदु का (y)-मान (y)-अवरोध होता है। इसलिए (c=6) है।
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If the line (y=mx+c) cuts the (y)-axis at ( (0,-9) ), what is (c)?
B. (-9)
On the (y)-axis, (x=0), and the (y)-value is (c). Therefore (c=-9).
The correct answer is B. (-9). On the (y)-axis, (x=0), and the (y)-value is (c). Therefore (c=-9).
(y)-अक्ष पर (x=0) होता है और (y)-मान (c) होता है। इसलिए (c=-9) है।
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Which line has slope (9) and (y)-intercept (-2)?
A. (y=9x-2)
For slope (9), the coefficient of (x) must be (9). With (y)-intercept (-2), the line is (y=9x-2).
The correct answer is A. (y=9x-2). For slope (9), the coefficient of (x) must be (9). With (y)-intercept (-2), the line is (y=9x-2).
ढाल (9) के लिए (x) का गुणांक (9) चाहिए। (y)-अवरोध (-2) से (y=9x-2) बनता है।
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Which line has slope (-6) and (y)-intercept (-8)?
B. (y=-6x-8)
Slope (-6) means the coefficient of (x) is (-6). With (y)-intercept (-8), (y=-6x-8) is correct.
The correct answer is B. (y=-6x-8). Slope (-6) means the coefficient of (x) is (-6). With (y)-intercept (-8), (y=-6x-8) is correct.
ढाल (-6) का अर्थ (x) का गुणांक (-6) है। (y)-अवरोध (-8) होने से (y=-6x-8) सही है।
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What is the (y)-intercept of the line \(y=\frac{9}{4}x+2\)?
C. (2)
The constant term is (2). Therefore the (y)-intercept is (2).
The correct answer is C. (2). The constant term is (2). Therefore the (y)-intercept is (2).
स्थिर पद (2) है। इसलिए (y)-अवरोध (2) है।
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What is the slope of the line \(y=-\frac{5}{9}x+8\)?
B. \(-\frac{5}{9}\)
The slope equals the coefficient of (x). Here the coefficient is \(-\frac{5}{9}\).
The correct answer is B. \(-\frac{5}{9}\). The slope equals the coefficient of (x). Here the coefficient is \(-\frac{5}{9}\).
ढाल (x) के गुणांक के बराबर होती है। यहां गुणांक \(-\frac{5}{9}\) है।
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At what (y)-value does the line (y=7x+20) cut the (y)-axis?
C. (20)
On the (y)-axis, (x=0). Then (y=20).
The correct answer is C. (20). On the (y)-axis, (x=0). Then (y=20).
(y)-अक्ष पर (x=0) होता है। तब (y=20) मिलता है।
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What is the sign of the slope of the line (y=-10x+31)?
C. ऋणात्मकNegative
The slope is (-10). Therefore its sign is negative.
The correct answer is C. ऋणात्मक / Negative. The slope is (-10). Therefore its sign is negative.
ढाल (-10) है। इसलिए उसका चिन्ह ऋणात्मक है।
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What is the sign of the slope of the line (y=14x-6)?
A. धनात्मकPositive
The slope is (14). Therefore its sign is positive.
The correct answer is A. धनात्मक / Positive. The slope is (14). Therefore its sign is positive.
ढाल (14) है। इसलिए उसका चिन्ह धनात्मक है।
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In the line (y=0x-7), what are the slope and (y)-intercept?
A. ढाल (0), (y)-अवरोध (-7)Slope (0), (y)-intercept (-7)
The coefficient of (x) is (0), and the constant term is (-7). So the slope is (0) and the (y)-intercept is (-7).
The correct answer is A. ढाल (0), (y)-अवरोध (-7) / Slope (0), (y)-intercept (-7). The coefficient of (x) is (0), and the constant term is (-7). So the slope is (0) and the (y)-intercept is (-7).
(x) का गुणांक (0) है और स्थिर पद (-7) है। इसलिए ढाल (0) और (y)-अवरोध (-7) है।
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In the line (y=21-8x), what are the coefficient of (x) and the constant term?
C. गुणांक (-8), स्थिर पद (21)Coefficient (-8), constant term (21)
We write it as (y=-8x+21). Therefore the coefficient of (x) is (-8), and the constant term is (21).
The correct answer is C. गुणांक (-8), स्थिर पद (21) / Coefficient (-8), constant term (21). We write it as (y=-8x+21). Therefore the coefficient of (x) is (-8), and the constant term is (21).
इसे (y=-8x+21) लिखते हैं। इसलिए (x) का गुणांक (-8) और स्थिर पद (21) है।
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At which point does the line (y=10-2x) cut the (y)-axis?
A. ( (0,10) )
On the (y)-axis, (x=0). Therefore the point is ( (0,10) ).
The correct answer is A. ( (0,10) ). On the (y)-axis, (x=0). Therefore the point is ( (0,10) ).
(y)-अक्ष पर (x=0) होता है। इसलिए बिंदु ( (0,10) ) है।
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In the line (y=-13x+6), what change occurs in (y) when (x) increases by (1)?
D. (13) घटता हैDecreases by (13)
The slope is (-13). So when (x) increases by (1), (y) decreases by (13).
The correct answer is D. (13) घटता है / Decreases by (13). The slope is (-13). So when (x) increases by (1), (y) decreases by (13).
ढाल (-13) है। इसलिए (x) के (1) बढ़ने पर (y) (13) घटता है।
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In the line (y=11x+13), by how much does (y) increase when (x) increases by (1)?
C. (11)
The slope is (11). So when (x) increases by (1), (y) increases by (11).
The correct answer is C. (11). The slope is (11). So when (x) increases by (1), (y) increases by (11).
ढाल (11) है। इसलिए (x) के (1) बढ़ने पर (y) (11) बढ़ता है।
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What is the slope of the line \(y=\frac{4}{3}x-6\)?
C. \(\frac{4}{3}\)
The slope equals the coefficient of (x). Here the coefficient is \(\frac{4}{3}\).
The correct answer is C. \(\frac{4}{3}\). The slope equals the coefficient of (x). Here the coefficient is \(\frac{4}{3}\).
ढाल (x) के गुणांक के बराबर होती है। यहां गुणांक \(\frac{4}{3}\) है।
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What is the (y)-intercept of the line \(y=-\frac{3}{8}x+5\)?
B. (5)
The constant term is (5). Therefore the (y)-intercept is (5).
The correct answer is B. (5). The constant term is (5). Therefore the (y)-intercept is (5).
स्थिर पद (5) है। इसलिए (y)-अवरोध (5) है।
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