At which point does the line (y=10-2x) cut the (y)-axis?
Answer and explanation
Correct answer: \((0,10)\)
At every point on the \(y\)-axis, \(x=0\). Substituting \(x=0\) in \(y=10-2x\) gives \(y=10\). Hence, the line cuts the \(y\)-axis at \((0,10)\). The point \((10,0)\) may relate to the \(x\)-intercept, but it is not on the \(y\)-axis. Exam tip: to find a \(y\)-intercept, always put \(x=0\).
Frequently asked questions
What is the correct answer to this question?
\((0,10)\)
Why is this the correct answer?
At every point on the \(y\)-axis, \(x=0\). Substituting \(x=0\) in \(y=10-2x\) gives \(y=10\). Hence, the line cuts the \(y\)-axis at \((0,10)\). The point \((10,0)\) may relate to the \(x\)-intercept, but it is not on the \(y\)-axis. Exam tip: to find a \(y\)-intercept, always put \(x=0\).
Which subject and chapter does this question cover?
This is a Class 9 Mathematics question. Chapter: Introduction to Polynomials. Topic: Slope and y-intercept.
Student feedback
Was this question useful?
👍 0 Helpful 👎 0 Not helpful
Yes 0% No 0%
0 responsesStudent Reviews
No published reviews yet.
