What is the (y)-intercept of the line (y=12x+0)?
Answer and explanation
Correct answer: 0
A line in the form \(y=mx+c\) has \(c\) as its \(y\)-intercept. In \(y=12x+0\), the constant term is \(0\), so the \(y\)-intercept is 0 and the line passes through the origin \((0,0)\). The number \(12\) is the slope, not the \(y\)-intercept. Exam tip: in \(y=mx+c\), the constant term gives the \(y\)-intercept directly.
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Why is this the correct answer?
A line in the form \(y=mx+c\) has \(c\) as its \(y\)-intercept. In \(y=12x+0\), the constant term is \(0\), so the \(y\)-intercept is 0 and the line passes through the origin \((0,0)\). The number \(12\) is the slope, not the \(y\)-intercept. Exam tip: in \(y=mx+c\), the constant term gives the \(y\)-intercept directly.
Which subject and chapter does this question cover?
This is a Class 9 Mathematics question. Chapter: Introduction to Polynomials. Topic: Slope and y-intercept.
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