Expert Mathematics Real Numbers Class 10 Level 21

किस भिन्न का दशमलव सांत है पर दिए गए हर में (31) भी दिखाई देता है?

Which fraction has a terminating decimal even though the given denominator contains (31)?

Explanation opens after your attempt
Correct Answer

A. \(\frac{62}{2^4\cdot 5^3\cdot 31}\)

Step 1

Concept

Since \(62=2\cdot 31\), the factor (31) cancels and the reduced denominator is \(2^3\cdot 5^3\). If an extra prime appears, check cancellation first.

Step 2

Why this answer is correct

The correct answer is A. \(\frac{62}{2^4\cdot 5^3\cdot 31}\). Since \(62=2\cdot 31\), the factor (31) cancels and the reduced denominator is \(2^3\cdot 5^3\). If an extra prime appears, check cancellation first.

Step 3

Exam Tip

\(62=2\cdot 31\) है इसलिए (31) कट जाता है और सरल हर \(2^3\cdot 5^3\) बचता है। अतिरिक्त अभाज्य गुणनखंड दिखे तो पहले कटौती देखें।

Related Mathematics Questions

FAQs

Mathematics Answer, Explanation and Revision Hints

किस भिन्न का दशमलव सांत है पर दिए गए हर में (31) भी दिखाई देता है? / Which fraction has a terminating decimal even though the given denominator contains (31)?

Correct Answer: A. \(\frac{62}{2^4\cdot 5^3\cdot 31}\). Explanation: \(62=2\cdot 31\) है इसलिए (31) कट जाता है और सरल हर \(2^3\cdot 5^3\) बचता है। अतिरिक्त अभाज्य गुणनखंड दिखे तो पहले कटौती देखें। / Since \(62=2\cdot 31\), the factor (31) cancels and the reduced denominator is \(2^3\cdot 5^3\). If an extra prime appears, check cancellation first.

Which concept should I revise for this Mathematics MCQ?

Since \(62=2\cdot 31\), the factor (31) cancels and the reduced denominator is \(2^3\cdot 5^3\). If an extra prime appears, check cancellation first.

What exam hint can help solve this Mathematics question?

\(62=2\cdot 31\) है इसलिए (31) कट जाता है और सरल हर \(2^3\cdot 5^3\) बचता है। अतिरिक्त अभाज्य गुणनखंड दिखे तो पहले कटौती देखें।

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