Concept-wise Practice

tricky-terminating MCQ Questions for Class 10

tricky-terminating se related questions ko ek jagah revise karein. Har question me bilingual content, answer feedback aur explanation available hai.

Practice Questions

3 questions tagged with tricky-terminating.

किस भिन्न का दशमलव सांत है पर दिए गए हर में (31) भी दिखाई देता है?

Which fraction has a terminating decimal even though the given denominator contains (31)?

Explanation opens after your attempt
Correct Answer

A. \(\frac{62}{2^4\cdot 5^3\cdot 31}\)

Step 1

Concept

Since \(62=2\cdot 31\), the factor (31) cancels and the reduced denominator is \(2^3\cdot 5^3\). If an extra prime appears, check cancellation first.

Step 2

Why this answer is correct

The correct answer is A. \(\frac{62}{2^4\cdot 5^3\cdot 31}\). Since \(62=2\cdot 31\), the factor (31) cancels and the reduced denominator is \(2^3\cdot 5^3\). If an extra prime appears, check cancellation first.

Step 3

Exam Tip

\(62=2\cdot 31\) है इसलिए (31) कट जाता है और सरल हर \(2^3\cdot 5^3\) बचता है। अतिरिक्त अभाज्य गुणनखंड दिखे तो पहले कटौती देखें।

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किस भिन्न का दशमलव सांत है पर दिए गए हर में (29) भी दिखाई देता है?

Which fraction has a terminating decimal even though the given denominator contains (29)?

Explanation opens after your attempt
Correct Answer

A. \(\frac{58}{2^3\cdot 5^2\cdot 29}\)

Step 1

Concept

Since \(58=2\cdot 29\), the factor (29) cancels and the reduced denominator is \(2^2\cdot 5^2\). If an extra prime appears, check cancellation first.

Step 2

Why this answer is correct

The correct answer is A. \(\frac{58}{2^3\cdot 5^2\cdot 29}\). Since \(58=2\cdot 29\), the factor (29) cancels and the reduced denominator is \(2^2\cdot 5^2\). If an extra prime appears, check cancellation first.

Step 3

Exam Tip

\(58=2\cdot 29\) है इसलिए (29) कट जाता है और सरल हर \(2^2\cdot 5^2\) बचता है। अतिरिक्त अभाज्य गुणनखंड दिखे तो पहले कटौती देखें।

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किस भिन्न का दशमलव सांत है पर दिए गए हर में (19) भी दिखता है?

Which fraction has a terminating decimal even though the given denominator contains (19)?

Explanation opens after your attempt
Correct Answer

B. \(\frac{38}{2^2\cdot 5^3\cdot 19}\)

Step 1

Concept

Since \(38=2\cdot 19\), the factor (19) cancels and the reduced denominator is \(2\cdot 5^3\). Even if an extra prime appears, check cancellation first.

Step 2

Why this answer is correct

The correct answer is B. \(\frac{38}{2^2\cdot 5^3\cdot 19}\). Since \(38=2\cdot 19\), the factor (19) cancels and the reduced denominator is \(2\cdot 5^3\). Even if an extra prime appears, check cancellation first.

Step 3

Exam Tip

\(38=2\cdot 19\), इसलिए (19) कट जाता है और सरल हर \(2\cdot 5^3\) बचता है। अतिरिक्त अभाज्य गुणनखंड दिखे तो भी पहले कटौती देखें।

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