किस भिन्न का दशमलव सांत है पर दिए गए हर में (19) भी दिखता है?
Which fraction has a terminating decimal even though the given denominator contains (19)?
Explanation opens after your attempt
Correct Answer
B. \(\frac{38}{2^2\cdot 5^3\cdot 19}\)
Concept
Since \(38=2\cdot 19\), the factor (19) cancels and the reduced denominator is \(2\cdot 5^3\). Even if an extra prime appears, check cancellation first.
Why this answer is correct
The correct answer is B. \(\frac{38}{2^2\cdot 5^3\cdot 19}\). Since \(38=2\cdot 19\), the factor (19) cancels and the reduced denominator is \(2\cdot 5^3\). Even if an extra prime appears, check cancellation first.
Exam Tip
\(38=2\cdot 19\), इसलिए (19) कट जाता है और सरल हर \(2\cdot 5^3\) बचता है। अतिरिक्त अभाज्य गुणनखंड दिखे तो भी पहले कटौती देखें।
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