\(\sqrt{6}\) का दशमलव विस्तार कैसा होगा?
What kind of decimal expansion does \(\sqrt{6}\) have?
Explanation opens after your attempt
Correct Answer
C. अनवसानी और अनावर्तीNon-terminating and non-recurring
Concept
(6) is not a perfect square.
Why this answer is correct
So \(\sqrt{6}\) is irrational and its decimal is non-terminating and non-recurring.
Exam Tip
An irrational number has no fixed repeating pattern. चरण 1: (6) पूर्ण वर्ग नहीं है। चरण 2: इसलिए \(\sqrt{6}\) अपरिमेय है और इसका दशमलव अनवसानी अनावर्ती होगा। चरण 3: अपरिमेय संख्या में स्थिर दोहराव नहीं होता।
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