\(\frac{1}{2^4\cdot 5^6\cdot 17}\) में आवर्ती भाग शुरू होने से पहले कितने अनावर्ती दशमलव अंक आएँगे?
In \(\frac{1}{2^4\cdot 5^6\cdot 17}\), how many non-repeating decimal digits appear before the recurring part starts?
Explanation opens after your attempt
Correct Answer
B. (6)
Concept
The factor (17) makes the decimal recurring, and the larger exponent among (2) and (5) is (6), giving the initial non-repeating part. Understand recurrence and delay separately.
Why this answer is correct
The correct answer is B. (6). The factor (17) makes the decimal recurring, and the larger exponent among (2) and (5) is (6), giving the initial non-repeating part. Understand recurrence and delay separately.
Exam Tip
(17) के कारण दशमलव आवर्ती होगा और (2), (5) की बड़ी घात (6) आरंभिक अनावर्ती भाग देगी। आवर्तीपन और आरंभिक देरी को अलग-अलग समझें।
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