यदि \(x=\sqrt{7}+\sqrt{28}\), तो \(\frac{x^2}{7}\) का मान क्या है?
If \(x=\sqrt{7}+\sqrt{28}\), what is the value of \(\frac{x^2}{7}\)?
Explanation opens after your attempt
A. (9)
Concept
\(\sqrt{28}=2\sqrt{7}\), so \(x=3\sqrt{7}\).
Why this answer is correct
(x-2=\(3\sqrt{7}\)2=63), hence \(\frac{x^2}{7}=9\).
Exam Tip
Combine like surds before squaring. चरण 1: \(\sqrt{28}=2\sqrt{7}\), इसलिए \(x=3\sqrt{7}\)। चरण 2: (x-2=\(3\sqrt{7}\)2=63), अतः \(\frac{x^2}{7}=9\)। चरण 3: वर्ग करने से पहले समान मूल वाले पद जोड़ना सरल रहता है।
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