यदि \(x=\sqrt{5}+\sqrt{2}\), तो (\(x^2-7\)2) का मान क्या है?
If \(x=\sqrt{5}+\sqrt{2}\), what is the value of (\(x^2-7\)2)?
Explanation opens after your attempt
A. (40)
Concept
\(x^2=5+2+2\sqrt{10}=7+2\sqrt{10}\).
Why this answer is correct
Thus \(x^2-7=2\sqrt{10}\), and its square is (40).
Exam Tip
First isolate the irrational part, then square it. चरण 1: \(x^2=5+2+2\sqrt{10}=7+2\sqrt{10}\)। चरण 2: इसलिए \(x^2-7=2\sqrt{10}\), और इसका वर्ग (40) है। चरण 3: पहले परिमेय भाग अलग करें, फिर वर्ग करें।
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