यदि \(x=\sqrt{2}+\sqrt{5}\), तो (\(x-\sqrt{2}\)2) का मान क्या है?
If \(x=\sqrt{2}+\sqrt{5}\), what is the value of (\(x-\sqrt{2}\)2)?
Explanation opens after your attempt
A. (5)
Concept
\(x-\sqrt{2}=\sqrt{5}\).
Why this answer is correct
Therefore (\(x-\sqrt{2}\)2=\(\sqrt{5}\)2=5).
Exam Tip
Simplify inside the bracket before expanding the square. चरण 1: \(x-\sqrt{2}=\sqrt{5}\) है। चरण 2: इसलिए (\(x-\sqrt{2}\)2=\(\sqrt{5}\)2=5)। चरण 3: पूरे वर्ग को फैलाने से पहले कोष्ठक के अंदर सरल करें।
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