Hard Mathematics Chapter 1: Real Numbers Class 10 Level 16

यदि \(\sqrt{3}\) की सिद्धि में (p=3r) और (q=3s) मिलते हैं, तो सबसे उचित विरोधाभास क्या है?

If (p=3r) and (q=3s) are obtained in the proof of \(\sqrt{3}\), what is the most appropriate contradiction?

Explanation opens after your attempt
Correct Answer

A. \(\frac{p}{q}\) सरलतम रूप में नहीं हो सकती\(\frac{p}{q}\) cannot be in lowest form

Step 1

Concept

(p=3r) and (q=3s) mean both (p) and (q) have common factor (3).

Step 2

Why this answer is correct

The numerator and denominator of a lowest-form fraction should be coprime.

Step 3

Exam Tip

Thus this contradicts the lowest-form assumption. चरण 1: (p=3r) और (q=3s) का अर्थ है कि (p) और (q) दोनों में (3) साझा गुणनखंड है। चरण 2: सरलतम भिन्न के अंश और हर सहअभाज्य होने चाहिए। चरण 3: इसलिए यह सरलतम रूप की मान्यता से विरोधाभास है।

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The correct answer is A. \(\frac{p}{q}\) सरलतम रूप में नहीं हो सकती / \(\frac{p}{q}\) cannot be in lowest form.

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