\(\frac{84}{2^3\cdot 3\cdot 5^2\cdot 7}\) को सरल करने के बाद दशमलव प्रसार कितने स्थानों पर समाप्त होगा?
After reducing \(\frac{84}{2^3\cdot 3\cdot 5^2\cdot 7}\), after how many decimal places will its decimal expansion terminate?
Explanation opens after your attempt
Correct Answer
B. (2) स्थान(2) places
Concept
Since \(84=2^2\cdot 3\cdot 7\), the reduced denominator is \(2\cdot 5^2\). The larger exponent is (2), so reduce first and then count places.
Why this answer is correct
The correct answer is B. (2) स्थान / (2) places. Since \(84=2^2\cdot 3\cdot 7\), the reduced denominator is \(2\cdot 5^2\). The larger exponent is (2), so reduce first and then count places.
Exam Tip
\(84=2^2\cdot 3\cdot 7\), इसलिए सरल हर \(2\cdot 5^2\) बचेगा। बड़ी घात (2) है, इसलिए पहले कटौती करें फिर स्थान गिनें।
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