\(\frac{242}{2^3\cdot 5^4\cdot 11^2}\) को सरलतम रूप में लिखने के बाद उसका दशमलव प्रसार कितने स्थानों पर समाप्त होगा?
After reducing \(\frac{242}{2^3\cdot 5^4\cdot 11^2}\) to lowest form, after how many decimal places will its decimal expansion terminate?
Explanation opens after your attempt
Correct Answer
B. (4) स्थान(4) places
Concept
Since \(242=2\cdot 11^2\), the reduced denominator becomes \(2^2\cdot 5^4\). The larger exponent is (4), so reduce first and then count decimal places.
Why this answer is correct
The correct answer is B. (4) स्थान / (4) places. Since \(242=2\cdot 11^2\), the reduced denominator becomes \(2^2\cdot 5^4\). The larger exponent is (4), so reduce first and then count decimal places.
Exam Tip
\(242=2\cdot 11^2\), इसलिए कटौती के बाद हर \(2^2\cdot 5^4\) बचेगा। बड़ी घात (4) है, इसलिए पहले सरल करें फिर दशमलव स्थान गिनें।
Login to save your score, XP, coins and progress.