\(\frac{72}{2^3\cdot 3^2\cdot 5^5}\) का दशमलव प्रसार कितने स्थानों पर समाप्त होगा?
After how many decimal places will \(\frac{72}{2^3\cdot 3^2\cdot 5^5}\) terminate?
Explanation opens after your attempt
Correct Answer
C. (5)
Concept
Since \(72=2^3\cdot 3^2\), the reduced denominator is \(5^5\). The decimal terminates after (5) places.
Why this answer is correct
The correct answer is C. (5). Since \(72=2^3\cdot 3^2\), the reduced denominator is \(5^5\). The decimal terminates after (5) places.
Exam Tip
\(72=2^3\cdot 3^2\), इसलिए कटौती के बाद हर \(5^5\) बचता है। दशमलव (5) स्थानों पर समाप्त होगा।
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