Medium Mathematics Chapter 1: Real Numbers Class 10 Level 16

\(\sqrt{3}\) को परिमेय मानने पर \(\sqrt{3}=\frac{p}{q}\) लिखा गया। यदि (p) और (q) में साझा गुणनखंड (3) मिल जाए, तो कौन सी मान्यता गलत सिद्ध होती है?

After assuming \(\sqrt{3}\) rational, \(\sqrt{3}=\frac{p}{q}\) is written. If common factor (3) is found in (p) and (q), which assumption is proved false?

Explanation opens after your attempt
Correct Answer

A. \(\sqrt{3}\) परिमेय है\(\sqrt{3}\) is rational

Step 1

Concept

After assuming rationality, (p) and (q) were taken coprime.

Step 2

Why this answer is correct

Finding common factor (3) makes this assumption impossible.

Step 3

Exam Tip

So the rational assumption is false and \(\sqrt{3}\) is irrational. चरण 1: परिमेय मानकर (p) और (q) को सहअभाज्य माना गया था। चरण 2: साझा गुणनखंड (3) मिलना इस मान्यता को असंभव बनाता है। चरण 3: इसलिए मूल परिमेय मान्यता गलत और \(\sqrt{3}\) अपरिमेय है।

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The correct answer is A. \(\sqrt{3}\) परिमेय है / \(\sqrt{3}\) is rational.

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