Find the (16)th term of the AP \(\frac{1}{2},1,\frac{3}{2},2,\ldots\).
C. (8)
यहाँ \(a=\frac{1}{2}\), \(d=\frac{1}{2}\) है, इसलिए \(a_{16}=\frac{1}{2}+15\times\frac{1}{2}=8\)। भिन्नों में हर समान रखकर जोड़ें। / Here \(a=\frac{1}{2}\), \(d=\frac{1}{2}\), so \(a_{16}=\frac{1}{2}+15\times\frac{1}{2}=8\). In fractions, keep denominators clear.
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Correct Answer: C. (8). Explanation: यहाँ \(a=\frac{1}{2}\), \(d=\frac{1}{2}\) है, इसलिए \(a_{16}=\frac{1}{2}+15\times\frac{1}{2}=8\)। भिन्नों में हर समान रखकर जोड़ें। / Here \(a=\frac{1}{2}\), \(d=\frac{1}{2}\), so \(a_{16}=\frac{1}{2}+15\times\frac{1}{2}=8\). In fractions, keep denominators clear.
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