\(x^2+\frac{1}{x}+4\) बहुपद क्यों नहीं है?
Why is \(x^2+\frac{1}{x}+4\) not a polynomial?
Explanation opens after your attempt
B. क्योंकि इसमें \(\frac{1}{x}\) है जिसकी घात (-1) हैBecause it has \(\frac{1}{x}\), whose power is (-1)
Concept
\(\frac{1}{x}=x^{-1}\). An expression with a negative power is not a polynomial.
Why this answer is correct
The correct answer is B. क्योंकि इसमें \(\frac{1}{x}\) है जिसकी घात (-1) है / Because it has \(\frac{1}{x}\), whose power is (-1). \(\frac{1}{x}=x^{-1}\). An expression with a negative power is not a polynomial.
Exam Tip
\(\frac{1}{x}=x^{-1}\) होता है। ऋणात्मक घात वाला व्यंजक बहुपद नहीं होता।
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