\(x^2+\frac{1}{x}+4\) बहुपद क्यों नहीं है?

Why is \(x^2+\frac{1}{x}+4\) not a polynomial?

Explanation opens after your attempt
Correct Answer

B. क्योंकि इसमें \(\frac{1}{x}\) है जिसकी घात (-1) हैBecause it has \(\frac{1}{x}\), whose power is (-1)

Step 1

Concept

\(\frac{1}{x}=x^{-1}\). An expression with a negative power is not a polynomial.

Step 2

Why this answer is correct

The correct answer is B. क्योंकि इसमें \(\frac{1}{x}\) है जिसकी घात (-1) है / Because it has \(\frac{1}{x}\), whose power is (-1). \(\frac{1}{x}=x^{-1}\). An expression with a negative power is not a polynomial.

Step 3

Exam Tip

\(\frac{1}{x}=x^{-1}\) होता है। ऋणात्मक घात वाला व्यंजक बहुपद नहीं होता।

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Mathematics Answer, Explanation and Revision Hints

\(x^2+\frac{1}{x}+4\) बहुपद क्यों नहीं है? / Why is \(x^2+\frac{1}{x}+4\) not a polynomial?

Correct Answer: B. क्योंकि इसमें \(\frac{1}{x}\) है जिसकी घात (-1) है / Because it has \(\frac{1}{x}\), whose power is (-1). Explanation: \(\frac{1}{x}=x^{-1}\) होता है। ऋणात्मक घात वाला व्यंजक बहुपद नहीं होता। / \(\frac{1}{x}=x^{-1}\). An expression with a negative power is not a polynomial.

Which concept should I revise for this Mathematics MCQ?

\(\frac{1}{x}=x^{-1}\). An expression with a negative power is not a polynomial.

What exam hint can help solve this Mathematics question?

\(\frac{1}{x}=x^{-1}\) होता है। ऋणात्मक घात वाला व्यंजक बहुपद नहीं होता।