व्यंजक \(x^2+\frac{1}{x^2}\) बहुपद क्यों नहीं है?
Why is \(x^2+\frac{1}{x^2}\) not a polynomial?
Explanation opens after your attempt
Correct Answer
C. क्योंकि \(\frac{1}{x^2}=x^{-2}\) हैBecause \(\frac{1}{x^2}=x^{-2}\)
Concept
In \(\frac{1}{x^2}\), the power of (x) is (-2). Due to the negative power, it is not a polynomial.
Why this answer is correct
The correct answer is C. क्योंकि \(\frac{1}{x^2}=x^{-2}\) है / Because \(\frac{1}{x^2}=x^{-2}\). In \(\frac{1}{x^2}\), the power of (x) is (-2). Due to the negative power, it is not a polynomial.
Exam Tip
\(\frac{1}{x^2}\) में (x) की घात (-2) है। ऋणात्मक घात के कारण यह बहुपद नहीं है।
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