वर्गमूल सर्पिल में \( \sqrt{n} \) पर अगला चरण \( \sqrt{n+1} \) क्यों बनता है?
Why does the next step after \( \sqrt{n} \) become \( \sqrt{n+1} \) in a square root spiral?
Explanation opens after your attempt
Correct Answer
D. क्योंकि ( \(\sqrt{n}\)2+12=n+1 )Because ( \(\sqrt{n}\)2+12=n+1 )
Concept
By Pythagoras, the square of the new hypotenuse is (n+1). Therefore the new hypotenuse is \( \sqrt{n+1} \).
Why this answer is correct
The correct answer is D. क्योंकि ( \(\sqrt{n}\)2+12=n+1 ) / Because ( \(\sqrt{n}\)2+12=n+1 ). By Pythagoras, the square of the new hypotenuse is (n+1). Therefore the new hypotenuse is \( \sqrt{n+1} \).
Exam Tip
पाइथागोरस प्रमेय से नए कर्ण का वर्ग (n+1) होता है। इसलिए नया कर्ण \( \sqrt{n+1} \) है।
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