व्यंजक \(3y^2+\sqrt{5}y-8\) के बारे में सही कथन कौन-सा है?

Which statement is correct about \(3y^2+\sqrt{5}y-8\)?

Explanation opens after your attempt
Correct Answer

D. यह (y) में बहुपद हैIt is a polynomial in (y)

Step 1

Concept

\(\sqrt{5}\) is only a real coefficient and is allowed. The powers of (y) are (2), (1), and (0).

Step 2

Why this answer is correct

The correct answer is D. यह (y) में बहुपद है / It is a polynomial in (y). \(\sqrt{5}\) is only a real coefficient and is allowed. The powers of (y) are (2), (1), and (0).

Step 3

Exam Tip

\(\sqrt{5}\) केवल वास्तविक गुणांक है और मान्य है। (y) की घातें (2), (1) और (0) हैं।

Question me issue ya doubt hai?

Answer, explanation, typing mistake ya suggestion directly hamari team ko bhejein. 📱Helpline (Call / WhatsApp): +91 7272824365

Related Mathematics Questions

FAQs

Mathematics Answer, Explanation and Revision Hints

व्यंजक \(3y^2+\sqrt{5}y-8\) के बारे में सही कथन कौन-सा है? / Which statement is correct about \(3y^2+\sqrt{5}y-8\)?

Correct Answer: D. यह (y) में बहुपद है / It is a polynomial in (y). Explanation: \(\sqrt{5}\) केवल वास्तविक गुणांक है और मान्य है। (y) की घातें (2), (1) और (0) हैं। / \(\sqrt{5}\) is only a real coefficient and is allowed. The powers of (y) are (2), (1), and (0).

Which concept should I revise for this Mathematics MCQ?

\(\sqrt{5}\) is only a real coefficient and is allowed. The powers of (y) are (2), (1), and (0).

What exam hint can help solve this Mathematics question?

\(\sqrt{5}\) केवल वास्तविक गुणांक है और मान्य है। (y) की घातें (2), (1) और (0) हैं।