वर्गमूल सर्पिल में \(\sqrt{49}\) और \(\sqrt{50}\) के बारे में कौन-सा कथन सही है?

Which statement about \(\sqrt{49}\) and \(\sqrt{50}\) in a square root spiral is correct?

Author: Muft Shiksha Editorial Team Published:
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Correct Answer

B. \(\sqrt{49}\) पूर्ण संख्या और \(\sqrt{50}\) अपरिमेय है\(\sqrt{49}\) is a whole number and \(\sqrt{50}\) is irrational

Step 1

Concept

\(\sqrt{49}=7\), but (50) is not a perfect square. Therefore \(\sqrt{50}\) is irrational.

Step 2

Why this answer is correct

The correct answer is B. \(\sqrt{49}\) पूर्ण संख्या और \(\sqrt{50}\) अपरिमेय है / \(\sqrt{49}\) is a whole number and \(\sqrt{50}\) is irrational. \(\sqrt{49}=7\), but (50) is not a perfect square. Therefore \(\sqrt{50}\) is irrational.

Step 3

Exam Tip

\(\sqrt{49}=7\) है, लेकिन (50) पूर्ण वर्ग नहीं है। इसलिए \(\sqrt{50}\) अपरिमेय है।

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वर्गमूल सर्पिल में \(\sqrt{49}\) और \(\sqrt{50}\) के बारे में कौन-सा कथन सही है? / Which statement about \(\sqrt{49}\) and \(\sqrt{50}\) in a square root spiral is correct?

Correct Answer: B. \(\sqrt{49}\) पूर्ण संख्या और \(\sqrt{50}\) अपरिमेय है / \(\sqrt{49}\) is a whole number and \(\sqrt{50}\) is irrational. Explanation: \(\sqrt{49}=7\) है, लेकिन (50) पूर्ण वर्ग नहीं है। इसलिए \(\sqrt{50}\) अपरिमेय है। / \(\sqrt{49}=7\), but (50) is not a perfect square. Therefore \(\sqrt{50}\) is irrational.

Which concept should I revise for this Mathematics MCQ?

\(\sqrt{49}=7\), but (50) is not a perfect square. Therefore \(\sqrt{50}\) is irrational.

What exam hint can help solve this Mathematics question?

\(\sqrt{49}=7\) है, लेकिन (50) पूर्ण वर्ग नहीं है। इसलिए \(\sqrt{50}\) अपरिमेय है।