वर्गमूल सर्पिल में \(\sqrt{36}\) और \(\sqrt{37}\) में कौन-सा कथन सही है?

Which statement about \(\sqrt{36}\) and \(\sqrt{37}\) in a square root spiral is correct?

Author: Muft Shiksha Editorial Team Published:
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Correct Answer

B. \(\sqrt{36}\) पूर्ण संख्या है और \(\sqrt{37}\) अपरिमेय है\(\sqrt{36}\) is a whole number and \(\sqrt{37}\) is irrational

Step 1

Concept

\(\sqrt{36}=6\), but (37) is not a perfect square. Therefore \(\sqrt{37}\) is irrational.

Step 2

Why this answer is correct

The correct answer is B. \(\sqrt{36}\) पूर्ण संख्या है और \(\sqrt{37}\) अपरिमेय है / \(\sqrt{36}\) is a whole number and \(\sqrt{37}\) is irrational. \(\sqrt{36}=6\), but (37) is not a perfect square. Therefore \(\sqrt{37}\) is irrational.

Step 3

Exam Tip

\(\sqrt{36}=6\) है, लेकिन (37) पूर्ण वर्ग नहीं है। इसलिए \(\sqrt{37}\) अपरिमेय है।

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Mathematics Answer, Explanation and Revision Hints

वर्गमूल सर्पिल में \(\sqrt{36}\) और \(\sqrt{37}\) में कौन-सा कथन सही है? / Which statement about \(\sqrt{36}\) and \(\sqrt{37}\) in a square root spiral is correct?

Correct Answer: B. \(\sqrt{36}\) पूर्ण संख्या है और \(\sqrt{37}\) अपरिमेय है / \(\sqrt{36}\) is a whole number and \(\sqrt{37}\) is irrational. Explanation: \(\sqrt{36}=6\) है, लेकिन (37) पूर्ण वर्ग नहीं है। इसलिए \(\sqrt{37}\) अपरिमेय है। / \(\sqrt{36}=6\), but (37) is not a perfect square. Therefore \(\sqrt{37}\) is irrational.

Which concept should I revise for this Mathematics MCQ?

\(\sqrt{36}=6\), but (37) is not a perfect square. Therefore \(\sqrt{37}\) is irrational.

What exam hint can help solve this Mathematics question?

\(\sqrt{36}=6\) है, लेकिन (37) पूर्ण वर्ग नहीं है। इसलिए \(\sqrt{37}\) अपरिमेय है।