\( \sqrt{2} \), \( \sqrt{3} \), और \( \sqrt{5} \) से बना कौन सा गुणनफल परिमेय है?

Which product made from \( \sqrt{2} \), \( \sqrt{3} \), and \( \sqrt{5} \) is rational?

Author: Muft Shiksha Editorial Team Published:
Explanation opens after your attempt
Correct Answer

A. \( \sqrt{2}\times\sqrt{8} \)

Step 1

Concept

\( \sqrt{2}\times\sqrt{8}=\sqrt{16}=4 \), which is rational. The other products do not become square roots of perfect squares.

Step 2

Why this answer is correct

The correct answer is A. \( \sqrt{2}\times\sqrt{8} \). \( \sqrt{2}\times\sqrt{8}=\sqrt{16}=4 \), which is rational. The other products do not become square roots of perfect squares.

Step 3

Exam Tip

\( \sqrt{2}\times\sqrt{8}=\sqrt{16}=4 \) परिमेय है। बाकी गुणनफल पूर्ण वर्ग के वर्गमूल में नहीं बदलते।

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FAQs

Mathematics Answer, Explanation and Revision Hints

\( \sqrt{2} \), \( \sqrt{3} \), और \( \sqrt{5} \) से बना कौन सा गुणनफल परिमेय है? / Which product made from \( \sqrt{2} \), \( \sqrt{3} \), and \( \sqrt{5} \) is rational?

Correct Answer: A. \( \sqrt{2}\times\sqrt{8} \). Explanation: \( \sqrt{2}\times\sqrt{8}=\sqrt{16}=4 \) परिमेय है। बाकी गुणनफल पूर्ण वर्ग के वर्गमूल में नहीं बदलते। / \( \sqrt{2}\times\sqrt{8}=\sqrt{16}=4 \), which is rational. The other products do not become square roots of perfect squares.

Which concept should I revise for this Mathematics MCQ?

\( \sqrt{2}\times\sqrt{8}=\sqrt{16}=4 \), which is rational. The other products do not become square roots of perfect squares.

What exam hint can help solve this Mathematics question?

\( \sqrt{2}\times\sqrt{8}=\sqrt{16}=4 \) परिमेय है। बाकी गुणनफल पूर्ण वर्ग के वर्गमूल में नहीं बदलते।