कौन सा विकल्प बताता है कि \(\sqrt{4}\) सर्पिल में बनने पर भी अपरिमेय नहीं है?
Which option explains why \(\sqrt{4}\) is not irrational even though it is formed in the spiral?
Explanation opens after your attempt
Correct Answer
A. क्योंकि \(\sqrt{4}=2\)Because \(\sqrt{4}=2\)
Concept
\(\sqrt{4}=2\), which is a rational number. Not all square roots formed in the spiral are irrational.
Why this answer is correct
The correct answer is A. क्योंकि \(\sqrt{4}=2\) / Because \(\sqrt{4}=2\). \(\sqrt{4}=2\), which is a rational number. Not all square roots formed in the spiral are irrational.
Exam Tip
\(\sqrt{4}=2\) है, जो परिमेय संख्या है। सर्पिल में बने सभी वर्गमूल अपरिमेय नहीं होते।
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