\(\sqrt{162}+\sqrt{98}-\sqrt{50}\) का सरल रूप कौन-सा है?
Which is the simplified form of \(\sqrt{162}+\sqrt{98}-\sqrt{50}\)?
Explanation opens after your attempt
Correct Answer
A. \(11\sqrt{2}\)
Concept
\(\sqrt{162}=9\sqrt{2}\), \(\sqrt{98}=7\sqrt{2}\), and \(\sqrt{50}=5\sqrt{2}\). Therefore the result is \(11\sqrt{2}\).
Why this answer is correct
The correct answer is A. \(11\sqrt{2}\). \(\sqrt{162}=9\sqrt{2}\), \(\sqrt{98}=7\sqrt{2}\), and \(\sqrt{50}=5\sqrt{2}\). Therefore the result is \(11\sqrt{2}\).
Exam Tip
\(\sqrt{162}=9\sqrt{2}\), \(\sqrt{98}=7\sqrt{2}\) और \(\sqrt{50}=5\sqrt{2}\) है। इसलिए परिणाम \(11\sqrt{2}\) है।
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