\(\frac{3+\sqrt{2}}{3-\sqrt{2}}\) का सरल रूप कौन-सा है?

Which is the simplified form of \(\frac{3+\sqrt{2}}{3-\sqrt{2}}\)?

Author: Muft Shiksha Editorial Team Published:
Explanation opens after your attempt
Correct Answer

A. \( \frac{11+6\sqrt{2}}{7}\)

Step 1

Concept

Multiplying by the conjugate gives denominator (9-2=7) and numerator (\(3+\sqrt{2}\)2=11+6\sqrt{2}). So the correct form is \(\frac{11+6\sqrt{2}}{7}\).

Step 2

Why this answer is correct

The correct answer is A. \( \frac{11+6\sqrt{2}}{7}\). Multiplying by the conjugate gives denominator (9-2=7) and numerator (\(3+\sqrt{2}\)2=11+6\sqrt{2}). So the correct form is \(\frac{11+6\sqrt{2}}{7}\).

Step 3

Exam Tip

संयुग्मी से गुणा करने पर हर (9-2=7) और अंश (\(3+\sqrt{2}\)2=11+6\sqrt{2}) मिलता है। इसलिए सही रूप \(\frac{11+6\sqrt{2}}{7}\) है।

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Mathematics Answer, Explanation and Revision Hints

\(\frac{3+\sqrt{2}}{3-\sqrt{2}}\) का सरल रूप कौन-सा है? / Which is the simplified form of \(\frac{3+\sqrt{2}}{3-\sqrt{2}}\)?

Correct Answer: A. \( \frac{11+6\sqrt{2}}{7}\). Explanation: संयुग्मी से गुणा करने पर हर (9-2=7) और अंश (\(3+\sqrt{2}\)2=11+6\sqrt{2}) मिलता है। इसलिए सही रूप \(\frac{11+6\sqrt{2}}{7}\) है। / Multiplying by the conjugate gives denominator (9-2=7) and numerator (\(3+\sqrt{2}\)2=11+6\sqrt{2}). So the correct form is \(\frac{11+6\sqrt{2}}{7}\).

Which concept should I revise for this Mathematics MCQ?

Multiplying by the conjugate gives denominator (9-2=7) and numerator (\(3+\sqrt{2}\)2=11+6\sqrt{2}). So the correct form is \(\frac{11+6\sqrt{2}}{7}\).

What exam hint can help solve this Mathematics question?

संयुग्मी से गुणा करने पर हर (9-2=7) और अंश (\(3+\sqrt{2}\)2=11+6\sqrt{2}) मिलता है। इसलिए सही रूप \(\frac{11+6\sqrt{2}}{7}\) है।