\(x^2+2x+1-y^2-4y-4\) का सही गुणनखंड कौन सा है?

Which is the correct factorisation of \(x^2+2x+1-y^2-4y-4\)?

Author: Muft Shiksha Editorial Team Published:
Explanation opens after your attempt
Correct Answer

A. ( (x-y-1)(x+y+3) )

Step 1

Concept

Write it as ((x+1)2-(y+2)2). On simplifying, we get ((x-y-1)(x+y+3)).

Step 2

Why this answer is correct

The correct answer is A. ( (x-y-1)(x+y+3) ). Write it as ((x+1)2-(y+2)2). On simplifying, we get ((x-y-1)(x+y+3)).

Step 3

Exam Tip

इसे ((x+1)2-(y+2)2) लिखें। सरल करने पर ((x-y-1)(x+y+3)) मिलता है।

Question me issue ya doubt hai?

Answer, explanation, typing mistake ya suggestion directly hamari team ko bhejein. 📱Helpline (Call / WhatsApp): +91 7272824365

Related Mathematics Questions

FAQs

Mathematics Answer, Explanation and Revision Hints

\(x^2+2x+1-y^2-4y-4\) का सही गुणनखंड कौन सा है? / Which is the correct factorisation of \(x^2+2x+1-y^2-4y-4\)?

Correct Answer: A. ( (x-y-1)(x+y+3) ). Explanation: इसे ((x+1)2-(y+2)2) लिखें। सरल करने पर ((x-y-1)(x+y+3)) मिलता है। / Write it as ((x+1)2-(y+2)2). On simplifying, we get ((x-y-1)(x+y+3)).

Which concept should I revise for this Mathematics MCQ?

Write it as ((x+1)2-(y+2)2). On simplifying, we get ((x-y-1)(x+y+3)).

What exam hint can help solve this Mathematics question?

इसे ((x+1)2-(y+2)2) लिखें। सरल करने पर ((x-y-1)(x+y+3)) मिलता है।