Which is greater between ( \frac{-1}{3} ) and ( \frac{-1}{6} )?

Correct answer: ( \frac{-1}{6} )

The direct answer is C, \\(\frac{-1}{6}\\). On a number line, among negative numbers the number closer to zero is greater. Compare the magnitudes: \\(\frac{1}{3}=\frac{2}{6}\\), so \\(\frac{-1}{3}=\frac{-2}{6}\\). Now compare \\(\frac{-2}{6}\\) and \\(\frac{-1}{6}\\): the latter is closer to zero, so it is greater. Equivalently, their decimal values are approximately \\(-0.333\\) and \\(-0.167\\); \\(-0.167\\) is greater. Option A is wrong because \\(\frac{-1}{3}\\) is farther left on the number line. Option B is wrong because the fractions have different values. Option C is correct because \\(\frac{-1}{6}>\frac{-1}{3}\\). Option D is wrong because the values are given exactly, so the comparison can be determined. Common mistake: thinking that the larger denominator automatically gives a smaller negative number without considering the sign. For negative fractions with the same numerator magnitude, the one closer to zero is larger.