वर्गमूल सर्पिल में \(\sqrt{32}\) को संख्या रेखा पर रखने के लिए कौन-सा अंतराल सही है?
Which interval is correct for placing \(\sqrt{32}\) on the number line using a square root spiral?
Explanation opens after your attempt
B. (5) और (6) के बीचBetween (5) and (6)
Concept
Because \(5^2<32<6^2\). Therefore \(\sqrt{32}\) lies between (5) and (6).
Why this answer is correct
The correct answer is B. (5) और (6) के बीच / Between (5) and (6). Because \(5^2<32<6^2\). Therefore \(\sqrt{32}\) lies between (5) and (6).
Exam Tip
क्योंकि \(5^2<32<6^2\) है। इसलिए \(\sqrt{32}\) (5) और (6) के बीच है।
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