\( \sqrt{a+b}=\sqrt{a}+\sqrt{b} \) को जाँचने के लिए कौन सा उदाहरण इसे गलत दिखाता है?

Which example shows that \( \sqrt{a+b}=\sqrt{a}+\sqrt{b} \) is false?

Author: Muft Shiksha Editorial Team Published:
Explanation opens after your attempt
Correct Answer

A. \( \sqrt{4+9}\neq\sqrt{4}+\sqrt{9} \)

Step 1

Concept

\( \sqrt{13} \) and (2+3=5) are not equal. Therefore square root cannot be distributed directly over addition.

Step 2

Why this answer is correct

The correct answer is A. \( \sqrt{4+9}\neq\sqrt{4}+\sqrt{9} \). \( \sqrt{13} \) and (2+3=5) are not equal. Therefore square root cannot be distributed directly over addition.

Step 3

Exam Tip

\( \sqrt{13} \) और (2+3=5) बराबर नहीं हैं। इसलिए वर्गमूल को जोड़ के अंदर सीधे नहीं बाँटते।

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Mathematics Answer, Explanation and Revision Hints

\( \sqrt{a+b}=\sqrt{a}+\sqrt{b} \) को जाँचने के लिए कौन सा उदाहरण इसे गलत दिखाता है? / Which example shows that \( \sqrt{a+b}=\sqrt{a}+\sqrt{b} \) is false?

Correct Answer: A. \( \sqrt{4+9}\neq\sqrt{4}+\sqrt{9} \). Explanation: \( \sqrt{13} \) और (2+3=5) बराबर नहीं हैं। इसलिए वर्गमूल को जोड़ के अंदर सीधे नहीं बाँटते। / \( \sqrt{13} \) and (2+3=5) are not equal. Therefore square root cannot be distributed directly over addition.

Which concept should I revise for this Mathematics MCQ?

\( \sqrt{13} \) and (2+3=5) are not equal. Therefore square root cannot be distributed directly over addition.

What exam hint can help solve this Mathematics question?

\( \sqrt{13} \) और (2+3=5) बराबर नहीं हैं। इसलिए वर्गमूल को जोड़ के अंदर सीधे नहीं बाँटते।