वर्गमूल सर्पिल में \(\sqrt{2}\) से \(\sqrt{3}\) बनने पर कौन-सी गलत धारणा से बचना चाहिए?

When \(\sqrt{3}\) is formed from \(\sqrt{2}\) in a square root spiral, which wrong idea should be avoided?

Author: Muft Shiksha Editorial Team Published:
Explanation opens after your attempt
Correct Answer

A. \(\sqrt{2}+1=\sqrt{3}\) माननाThinking \(\sqrt{2}+1=\sqrt{3}\)

Step 1

Concept

\(\sqrt{3}\) is formed from the sum of squares, not direct addition. The correct calculation is (\(\sqrt{2}\)2+12=3).

Step 2

Why this answer is correct

The correct answer is A. \(\sqrt{2}+1=\sqrt{3}\) मानना / Thinking \(\sqrt{2}+1=\sqrt{3}\). \(\sqrt{3}\) is formed from the sum of squares, not direct addition. The correct calculation is (\(\sqrt{2}\)2+12=3).

Step 3

Exam Tip

\(\sqrt{3}\) वर्गों के योग से बनता है, सीधे जोड़ से नहीं। सही गणना (\(\sqrt{2}\)2+12=3) है।

Question me issue ya doubt hai?

Answer, explanation, typing mistake ya suggestion directly hamari team ko bhejein. 📱Helpline (Call / WhatsApp): +91 7272824365

Related Mathematics Questions

FAQs

Mathematics Answer, Explanation and Revision Hints

वर्गमूल सर्पिल में \(\sqrt{2}\) से \(\sqrt{3}\) बनने पर कौन-सी गलत धारणा से बचना चाहिए? / When \(\sqrt{3}\) is formed from \(\sqrt{2}\) in a square root spiral, which wrong idea should be avoided?

Correct Answer: A. \(\sqrt{2}+1=\sqrt{3}\) मानना / Thinking \(\sqrt{2}+1=\sqrt{3}\). Explanation: \(\sqrt{3}\) वर्गों के योग से बनता है, सीधे जोड़ से नहीं। सही गणना (\(\sqrt{2}\)2+12=3) है। / \(\sqrt{3}\) is formed from the sum of squares, not direct addition. The correct calculation is (\(\sqrt{2}\)2+12=3).

Which concept should I revise for this Mathematics MCQ?

\(\sqrt{3}\) is formed from the sum of squares, not direct addition. The correct calculation is (\(\sqrt{2}\)2+12=3).

What exam hint can help solve this Mathematics question?

\(\sqrt{3}\) वर्गों के योग से बनता है, सीधे जोड़ से नहीं। सही गणना (\(\sqrt{2}\)2+12=3) है।