\(\sqrt{98}-\sqrt{32}\) का मान क्या है?
What is the value of \(\sqrt{98}-\sqrt{32}\)?
Explanation opens after your attempt
A. \(\sqrt{2}\)
Concept
\(7\sqrt{2}-4\sqrt{2}=3\sqrt{2}\). Simplify first.
Why this answer is correct
The correct answer is A. \(\sqrt{2}\). \(7\sqrt{2}-4\sqrt{2}=3\sqrt{2}\). Simplify first.
Exam Tip
\(7\sqrt{2}-4\sqrt{2}=3\sqrt{2}\)। पहले सरल करें।
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