\( \frac{2+\sqrt{3}}{2-\sqrt{3}} \) का परिमेय हर करने पर मान क्या होगा?

What is the value of \( \frac{2+\sqrt{3}}{2-\sqrt{3}} \) after rationalising?

Author: Muft Shiksha Editorial Team Published:
Explanation opens after your attempt
Correct Answer

A. \(7+4\sqrt{3}\)

Step 1

Concept

Multiply by the conjugate \(2+\sqrt{3}\). The numerator becomes (\(2+\sqrt{3}\)2=7+4\sqrt{3}) and the denominator becomes (1).

Step 2

Why this answer is correct

The correct answer is A. \(7+4\sqrt{3}\). Multiply by the conjugate \(2+\sqrt{3}\). The numerator becomes (\(2+\sqrt{3}\)2=7+4\sqrt{3}) and the denominator becomes (1).

Step 3

Exam Tip

हर के संयुग्मी \(2+\sqrt{3}\) से गुणा करें। अंश (\(2+\sqrt{3}\)2=7+4\sqrt{3}) और हर (1) होगा।

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Mathematics Answer, Explanation and Revision Hints

\( \frac{2+\sqrt{3}}{2-\sqrt{3}} \) का परिमेय हर करने पर मान क्या होगा? / What is the value of \( \frac{2+\sqrt{3}}{2-\sqrt{3}} \) after rationalising?

Correct Answer: A. \(7+4\sqrt{3}\). Explanation: हर के संयुग्मी \(2+\sqrt{3}\) से गुणा करें। अंश (\(2+\sqrt{3}\)2=7+4\sqrt{3}) और हर (1) होगा। / Multiply by the conjugate \(2+\sqrt{3}\). The numerator becomes (\(2+\sqrt{3}\)2=7+4\sqrt{3}) and the denominator becomes (1).

Which concept should I revise for this Mathematics MCQ?

Multiply by the conjugate \(2+\sqrt{3}\). The numerator becomes (\(2+\sqrt{3}\)2=7+4\sqrt{3}) and the denominator becomes (1).

What exam hint can help solve this Mathematics question?

हर के संयुग्मी \(2+\sqrt{3}\) से गुणा करें। अंश (\(2+\sqrt{3}\)2=7+4\sqrt{3}) और हर (1) होगा।