\(\frac{1}{\sqrt{12}+\sqrt{5}}+\frac{1}{\sqrt{12}-\sqrt{5}}\) का मान क्या है?

What is the value of \(\frac{1}{\sqrt{12}+\sqrt{5}}+\frac{1}{\sqrt{12}-\sqrt{5}}\)?

Author: Muft Shiksha Editorial Team Published:
Explanation opens after your attempt
Correct Answer

C. \(\frac{4\sqrt{3}}{7}\)

Step 1

Concept

Adding both fractions gives numerator \(2\sqrt{12}\) and denominator (12-5=7). So the value is \(\frac{4\sqrt{3}}{7}\).

Step 2

Why this answer is correct

The correct answer is C. \(\frac{4\sqrt{3}}{7}\). Adding both fractions gives numerator \(2\sqrt{12}\) and denominator (12-5=7). So the value is \(\frac{4\sqrt{3}}{7}\).

Step 3

Exam Tip

दोनों भिन्नों को जोड़ने पर अंश \(2\sqrt{12}\) और हर (12-5=7) मिलता है। इसलिए मान \(\frac{4\sqrt{3}}{7}\) है।

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FAQs

Mathematics Answer, Explanation and Revision Hints

\(\frac{1}{\sqrt{12}+\sqrt{5}}+\frac{1}{\sqrt{12}-\sqrt{5}}\) का मान क्या है? / What is the value of \(\frac{1}{\sqrt{12}+\sqrt{5}}+\frac{1}{\sqrt{12}-\sqrt{5}}\)?

Correct Answer: C. \(\frac{4\sqrt{3}}{7}\). Explanation: दोनों भिन्नों को जोड़ने पर अंश \(2\sqrt{12}\) और हर (12-5=7) मिलता है। इसलिए मान \(\frac{4\sqrt{3}}{7}\) है। / Adding both fractions gives numerator \(2\sqrt{12}\) and denominator (12-5=7). So the value is \(\frac{4\sqrt{3}}{7}\).

Which concept should I revise for this Mathematics MCQ?

Adding both fractions gives numerator \(2\sqrt{12}\) and denominator (12-5=7). So the value is \(\frac{4\sqrt{3}}{7}\).

What exam hint can help solve this Mathematics question?

दोनों भिन्नों को जोड़ने पर अंश \(2\sqrt{12}\) और हर (12-5=7) मिलता है। इसलिए मान \(\frac{4\sqrt{3}}{7}\) है।