\(\sqrt{12+\sqrt{35}}\) का वर्ग किसके बराबर है?
What is the square of \(\sqrt{12+\sqrt{35}}\) equal to?
Explanation opens after your attempt
A. \(12+\sqrt{35}\)
Concept
The square of a square root gives the number inside. So (\left\(\sqrt{12+\sqrt{35}}\right\)2=12+\sqrt{35}).
Why this answer is correct
The correct answer is A. \(12+\sqrt{35}\). The square of a square root gives the number inside. So (\left\(\sqrt{12+\sqrt{35}}\right\)2=12+\sqrt{35}).
Exam Tip
वर्गमूल का वर्ग अंदर की संख्या देता है। इसलिए (\left\(\sqrt{12+\sqrt{35}}\right\)2=12+\sqrt{35}) है।
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