\(\sqrt{12+\sqrt{35}}\) का वर्ग किसके बराबर है?

What is the square of \(\sqrt{12+\sqrt{35}}\) equal to?

Author: Muft Shiksha Editorial Team Published:
Explanation opens after your attempt
Correct Answer

A. \(12+\sqrt{35}\)

Step 1

Concept

The square of a square root gives the number inside. So (\left\(\sqrt{12+\sqrt{35}}\right\)2=12+\sqrt{35}).

Step 2

Why this answer is correct

The correct answer is A. \(12+\sqrt{35}\). The square of a square root gives the number inside. So (\left\(\sqrt{12+\sqrt{35}}\right\)2=12+\sqrt{35}).

Step 3

Exam Tip

वर्गमूल का वर्ग अंदर की संख्या देता है। इसलिए (\left\(\sqrt{12+\sqrt{35}}\right\)2=12+\sqrt{35}) है।

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Mathematics Answer, Explanation and Revision Hints

\(\sqrt{12+\sqrt{35}}\) का वर्ग किसके बराबर है? / What is the square of \(\sqrt{12+\sqrt{35}}\) equal to?

Correct Answer: A. \(12+\sqrt{35}\). Explanation: वर्गमूल का वर्ग अंदर की संख्या देता है। इसलिए (\left\(\sqrt{12+\sqrt{35}}\right\)2=12+\sqrt{35}) है। / The square of a square root gives the number inside. So (\left\(\sqrt{12+\sqrt{35}}\right\)2=12+\sqrt{35}).

Which concept should I revise for this Mathematics MCQ?

The square of a square root gives the number inside. So (\left\(\sqrt{12+\sqrt{35}}\right\)2=12+\sqrt{35}).

What exam hint can help solve this Mathematics question?

वर्गमूल का वर्ग अंदर की संख्या देता है। इसलिए (\left\(\sqrt{12+\sqrt{35}}\right\)2=12+\sqrt{35}) है।