\(\frac{7}{\sqrt{19}-\sqrt{12}}\) का परिमेयकृत रूप क्या है?
What is the rationalised form of \(\frac{7}{\sqrt{19}-\sqrt{12}}\)?
Explanation opens after your attempt
Correct Answer
A. \(\sqrt{19}+\sqrt{12}\)
Concept
Multiplying by the conjugate makes the denominator (19-12=7). So (\frac{7\(\sqrt{19}+\sqrt{12}\)}{7}=\sqrt{19}+\sqrt{12}).
Why this answer is correct
The correct answer is A. \(\sqrt{19}+\sqrt{12}\). Multiplying by the conjugate makes the denominator (19-12=7). So (\frac{7\(\sqrt{19}+\sqrt{12}\)}{7}=\sqrt{19}+\sqrt{12}).
Exam Tip
संयुग्मी से गुणा करने पर हर (19-12=7) बनता है। इसलिए (\frac{7\(\sqrt{19}+\sqrt{12}\)}{7}=\sqrt{19}+\sqrt{12}) है।
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