\(\frac{2}{\sqrt{11}+\sqrt{7}}\) का परिमेयकृत रूप क्या है?
What is the rationalised form of \(\frac{2}{\sqrt{11}+\sqrt{7}}\)?
Explanation opens after your attempt
Correct Answer
B. \(\frac{\sqrt{11}-\sqrt{7}}{2}\)
Concept
Multiplying by the conjugate makes the denominator (11-7=4). So (\frac{2\(\sqrt{11}-\sqrt{7}\)}{4}=\frac{\sqrt{11}-\sqrt{7}}{2}).
Why this answer is correct
The correct answer is B. \(\frac{\sqrt{11}-\sqrt{7}}{2}\). Multiplying by the conjugate makes the denominator (11-7=4). So (\frac{2\(\sqrt{11}-\sqrt{7}\)}{4}=\frac{\sqrt{11}-\sqrt{7}}{2}).
Exam Tip
संयुग्मी से गुणा करने पर हर (11-7=4) बनता है। इसलिए (\frac{2\(\sqrt{11}-\sqrt{7}\)}{4}=\frac{\sqrt{11}-\sqrt{7}}{2}) है।
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