\( \frac{1}{\sqrt{3}+\sqrt{2}} \) का परिमेय हर वाला रूप क्या है?

What is the rationalised form of \( \frac{1}{\sqrt{3}+\sqrt{2}} \)?

Author: Muft Shiksha Editorial Team Published:
Explanation opens after your attempt
Correct Answer

C. \( \sqrt{3}-\sqrt{2} \)

Step 1

Concept

Multiplying by the conjugate \( \sqrt{3}-\sqrt{2} \) makes the denominator (3-2=1). So the rationalised form is \( \sqrt{3}-\sqrt{2} \).

Step 2

Why this answer is correct

The correct answer is C. \( \sqrt{3}-\sqrt{2} \). Multiplying by the conjugate \( \sqrt{3}-\sqrt{2} \) makes the denominator (3-2=1). So the rationalised form is \( \sqrt{3}-\sqrt{2} \).

Step 3

Exam Tip

संयुग्मी \( \sqrt{3}-\sqrt{2} \) से गुणा करने पर हर (3-2=1) बनता है। इसलिए परिमेय हर वाला रूप \( \sqrt{3}-\sqrt{2} \) है।

Question me issue ya doubt hai?

Answer, explanation, typing mistake ya suggestion directly hamari team ko bhejein. 📱Helpline (Call / WhatsApp): +91 7272824365

Related Mathematics Questions

FAQs

Mathematics Answer, Explanation and Revision Hints

\( \frac{1}{\sqrt{3}+\sqrt{2}} \) का परिमेय हर वाला रूप क्या है? / What is the rationalised form of \( \frac{1}{\sqrt{3}+\sqrt{2}} \)?

Correct Answer: C. \( \sqrt{3}-\sqrt{2} \). Explanation: संयुग्मी \( \sqrt{3}-\sqrt{2} \) से गुणा करने पर हर (3-2=1) बनता है। इसलिए परिमेय हर वाला रूप \( \sqrt{3}-\sqrt{2} \) है। / Multiplying by the conjugate \( \sqrt{3}-\sqrt{2} \) makes the denominator (3-2=1). So the rationalised form is \( \sqrt{3}-\sqrt{2} \).

Which concept should I revise for this Mathematics MCQ?

Multiplying by the conjugate \( \sqrt{3}-\sqrt{2} \) makes the denominator (3-2=1). So the rationalised form is \( \sqrt{3}-\sqrt{2} \).

What exam hint can help solve this Mathematics question?

संयुग्मी \( \sqrt{3}-\sqrt{2} \) से गुणा करने पर हर (3-2=1) बनता है। इसलिए परिमेय हर वाला रूप \( \sqrt{3}-\sqrt{2} \) है।