वर्गमूल सर्पिल में \(\sqrt{3480}\) का सही अंतराल कौन-सा है?

What is the correct interval for \(\sqrt{3480}\) in a square root spiral?

Author: Muft Shiksha Editorial Team Published:
Explanation opens after your attempt
Correct Answer

B. \(58<\sqrt{3480}<59\)

Step 1

Concept

\(58^2=3364\) and \(59^2=3481\). The number (3480) lies between them, so \(\sqrt{3480}\) lies between (58) and (59).

Step 2

Why this answer is correct

The correct answer is B. \(58<\sqrt{3480}<59\). \(58^2=3364\) and \(59^2=3481\). The number (3480) lies between them, so \(\sqrt{3480}\) lies between (58) and (59).

Step 3

Exam Tip

\(58^2=3364\) और \(59^2=3481\) हैं। (3480) इनके बीच है, इसलिए \(\sqrt{3480}\) (58) और (59) के बीच है।

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Mathematics Answer, Explanation and Revision Hints

वर्गमूल सर्पिल में \(\sqrt{3480}\) का सही अंतराल कौन-सा है? / What is the correct interval for \(\sqrt{3480}\) in a square root spiral?

Correct Answer: B. \(58<\sqrt{3480}<59\). Explanation: \(58^2=3364\) और \(59^2=3481\) हैं। (3480) इनके बीच है, इसलिए \(\sqrt{3480}\) (58) और (59) के बीच है। / \(58^2=3364\) and \(59^2=3481\). The number (3480) lies between them, so \(\sqrt{3480}\) lies between (58) and (59).

Which concept should I revise for this Mathematics MCQ?

\(58^2=3364\) and \(59^2=3481\). The number (3480) lies between them, so \(\sqrt{3480}\) lies between (58) and (59).

What exam hint can help solve this Mathematics question?

\(58^2=3364\) और \(59^2=3481\) हैं। (3480) इनके बीच है, इसलिए \(\sqrt{3480}\) (58) और (59) के बीच है।